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Phantasy [73]
3 years ago
9

ANIMALS A chicken can run at a top speed of 9 miles per hour. Find the top speed of a chicken in miles per minute. Round to the

nearest tenth.
Mathematics
1 answer:
NISA [10]3 years ago
5 0
<span>
1.You first have to determine the relationship and the current unit and the target unit which it will be converted into....</span> <span>
2.In this case, feet to meters and seconds to minutes</span> <span>
3.Determine the conversion rate</span>
<span>4 <span>The time which is 2 mi / hr x 1 hr / 60 min =  0.3 mi/min</span></span><span> 
</span><span>And that's your answer :)</span>
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The mean of the data is 3 inches, is false

Step-by-step explanation:

3, 3, 4, 4, and 6 inches.

To find the mean, add the numbers together and divide by the number of data points

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2 years ago
Solve for x. −4≤16−4x
Nitella [24]

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the answer for x<5

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

−4<−4x+16

Step 2: Flip the equation.

−4x+16>−4

Step 3: Subtract 16 from both sides.

−4x+16−16>−4−16

−4x>−20

Step 4: Divide both sides by -4.

−4x

−4

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−20

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4 0
3 years ago
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solve for a dairy needs 275 gallons of milk containing 5% butterfat. how many gallons each of milk containing 7% butterfat and m
Kazeer [188]
X = gallons of the 7% butterfat milk

y = gallons of the 2% butterfat milk


now, we'll be adding "x" gallons of the 7% one, but we know that, is really "x" gallons, but only 7% of it is butterfat, the rest is water and other subtances.

so, in "x" gallons, how many gallons is butterfat only anyway?  namely, what is 7% of "x"?  well, (7/100) * x, or 0.07x.

likewise, how many gallons of butterfat are in the 2% one?  well, (2/100) * "y" or 0.02y.

we know that, whatever "x" and "y" add up to 275 gallons, thus x + y = 275.

we also know that, the butterfat amounts add up to the same butterfat in the 275 gallons, thus

\bf \begin{array}{lccclll}&#10;&\stackrel{gallons}{amount}&\stackrel{butterfat~\%}{quantity}&\stackrel{butterfat~gallons}{quantity}\\&#10;&------&------&------\\&#10;\textit{7\% butterfat milk}&x&0.07&0.07x\\&#10;\textit{2\% butterfat milk}&y&0.02&0.02y\\&#10;--------&------&------&------\\&#10;mixture&275&0.05&13.75&#10;\end{array}

\bf \begin{cases}&#10;x+y=275\implies \boxed{y}=275-x\\&#10;0.07x+0.02y=13.75\\&#10;----------\\&#10;0.07x+0.02\left( \boxed{275-x} \right)=13.75&#10;\end{cases}&#10;\\\\\\&#10;0.07x-0.02x+5.50=13.75\implies 0.05x=8.25&#10;\\\\\\&#10;x=\cfrac{8.25}{0.05}\implies x=165

how much will it be of the 2% milk?  well, y = 275 - x.
7 0
3 years ago
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