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3 years ago

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Phillip is mowing his backyard. His backyard is oddly shaped. Phillip has an 8 ft by 8 ft pond in his backyard. What is the tota

l area that Phillip will be mowing?

1 answer:

Verdich [7]3 years ago

8 0

I'm not a 100% sure but I think it is 64 ft if somebody see this and see that I'm wrong please correct me

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Kiran starts at 9:00 am by bicycle to reach office. She cycles at the speed of 8 km/hour and reaches the office at 9:15 am. By h

Ivenika [448]

Answer:

v = 12 km/h

Step-by-step explanation:

To find how much she should increase the speed first we need to find the distance traveled:

$d = v*t$

Where:

d: is the distance traveled =?

v: is the velocity = 8 km/h

t: is the time = 15 min (9:00 to 9:15)

$d = v*t = 8 km/h*15 min*\frac{1 h}{60 min} = 2 km$

Now, we can find the speed:

$v_{f} = \frac{d}{t} = \frac{2 km}{10 min*\frac{1 h}{60 min}} = 12 km/h$

Therefore, she should increase the speed to 12 km/h to reach the office at 9:10 am.

I hope it helps you!

6 0

3 years ago

Solve:<br> y = 2x -11<br> -3y = -6x -15

Nikolay [14]

9514 1404 393

Answer:

no solution (parallel lines)

Step-by-step explanation:

You observe that the coefficient in the second equation are all multiples of 3. Dividing that equation by -3 gives the two equations ...

y = 2x - 11
y = 2x + 5

The slopes are the same (2) and the intercepts are different (-11, 5), so the lines are parallel. There is no solution.

7 0

3 years ago

Solve the following equation by factoring:9x^2-3x-2=0

olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

$x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}$

Step-by-step explanation:

Original quadratic equation is $9x^{2}-3x-2=0$

Divide both sides by 9:

$x^{2} - \frac{x}{3} - \frac{2}{9}=0$

Add $\frac{2}{9}$ to both sides to get rid of the constant on the LHS

$x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}$ ==> $x^{2} - \frac{x}{3}=\frac{2}{9}$

Add $\frac{1}{36}$ to both sides

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}$

This simplifies to

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}$

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = $\frac{1}{6}\right)$ we can see that

$\left(x - \frac{1}{6}\right)^2$ = $x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}$

So

$\left(x - \frac{1}{6}\right)^2=\frac{1}{4}$

Taking square roots on both sides

$\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}$

So the two roots or solutions of the equation are

$x - \frac{1}{6}=-\sqrt{\frac{1}{4}}$ and $x - \frac{1}{6}=\sqrt{\frac{1}{4}}$

$\sqrt{\frac{1}{4}} = \frac{1}{2}$

So the two roots are

$x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}$

and

$x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}$

7 0

2 years ago

Which measure of central tendency is least appropriate for describing the given data set?

beks73 [17]

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

6, 6, 6, 7, 8, 8, 29

We will calculate the measures of central tendency:

1) Mode - the most occurring element in the data set.

So, Mode = 6

2) Median - the middle value of organised data set

So, Median = 7

3) Mean - the average of all data set

So, Mean = $\dfrac{6+6+6+7+8+8+29}{7}=\dfrac{70}{7}=10$

So, we can see that Mode and Median are giving the closest value to each other, whereas Mean is giving the farthest value as compared to rest.

Hence, Mean is the least appropriate for describing the given data set.

Thus, Third option is correct.

3 0

3 years ago

Find the prime factorization of 196. Use a method of your choice. List your final answer

hammer [34]

Positive Integer factors of 196 = 2, 4, 7, 28, 196 divided by 2, 2, 7, 7, gives no remainder. If we put all of it together we have the factors 2 x 2 x 7 x 7 = 196. It can also be written in exponential form as 22 x 72.

(I got all of this from google so i hope it’s right!)

3 0

3 years ago