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3 years ago

9

Given the sets A = {7, 11, 14, 17, 21} and B = {0, 11, 15, 17, 34}, the set A∩B is given by:

1 answer:

Masja [62]3 years ago

8 0

Pick the numbers that are in BOTH sets<span><span>anonymous </span> 3 years ago</span>find the numbers that are common to A∩B , this is where a and b intersect<span><span>anonymous </span> 3 years ago</span>would the answer be a? because those numbers are in both sets A & B ?

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3. "A boat travels 160 miles in 5 hours. What is the

8090 [49]

Answer:

3. = 32 4. = 54 min

Step-by-step explanation:

4 0

2 years ago

Which equations have the same value of x as Two-thirds (6 x + 12) = negative 24? Select two options.

Anna71 [15]

Answer:

4x+8=-24 and

4x=-32

Step-by-step explanation:

2/3(6x+12)=-24

or,12x+24=-72

or,x=-72-24/12

•°•x=-8

4x+8=-24

or,x=-24-8/4

•°•x=-8

4x=-32

or,x=-32/4

•°•x=-8

4 0

3 years ago

Read 2 more answers

What is 9/10 minus 3/5

madam [21]

9/10

3/5 *2/2 +6/10

9/10-6/10=3/10 or .3

8 0

3 years ago

Read 2 more answers

On the trip from KC to Springfield, the church van consumed 15 gallons of gas to go 179 miles. If gas cost $2.58 per gallon, wha

Otrada [13]

Answer:

$77.4

Step-by-step explanation:

GIVEN: On the trip from KC to Springfield, the church van consumed $15$ gallons of gas to go $179$ miles. If gas cost $\$2.58$ per gallon.

TO FIND: Cost of a round trip to Springfield.

SOLUTION:

Distance of springfield from KC $=179\text{ miles}$

As it is a round trip total distance $=2\times179=358\text{ miles}$

As $15$ gallons gas used for $179$ miles distance

gas required for $1$ mile $=\frac{15}{179}$ gallons

gas required for $358$ miles $=\frac{15}{179}\times2=30$ gallons

cost of one gallon of gas $=\$2.58$

cost of $30$ gallons of gas $=30\times2.58=\$77.4$

Hence cost of roundtrip to Springfield is $77.4

6 0

3 years ago

Suppose that X is a random variable that has a binomial uncertainty distribution with parameters n = 10 and π = 0.4. Calculate t

swat32

The numerical values of the mean and standard deviation are 4 and 1.55, respectively

<h3>The numerical value of the probability that x = 6. </h3>

The given parameters are:

n = 10

π = 0.4

The probability is then calculated as:

$P(x) = ^nC_x * \pi^x *(1-\pi)^{n-x}$

So, we have:

$P(6) = ^{10}C_6 * 0.4^6 *(1-0.4)^4$

Apply the combination formula

$P(6) = \frac{10!}{6!4!} * 0.4^6 *0.6^4$

So, we have:

$P(6) = 210 * 0.4^6 *0.6^4$

Evaluate

P(6) = 0.1115

Hence, the numerical value of the probability that x = 6 is 0.1115

<h3>The numerical values of the mean and standard deviation </h3>

The mean value is:

$\bar x = n\pi$

This gives

$\bar x = 10 * 0.4$

$\bar x = 4$

The standard deviation value is:

$\sigma = \sqrt{\bar x(1-\pi)$

This gives

$\sigma = \sqrt{4(1-0.4)$

$\sigma = 1.55$

Hence, the numerical values of the mean and standard deviation are 4 and 1.55, respectively

Read more about mean and standard deviation at:

brainly.com/question/16030790

#SPJ1

8 0

2 years ago