Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
C. people have to buy entire albums, which can get expensive.
Answer:
monkey know monkey not tell
Explanation:
Answer:
#include <iostream>
using namespace std;
class ProblemSolution {
private:
int num1, num2;
public:
ProblemSolution(int n1, int n2) {
num1 = n1;
num2 = n2;
}
int calculateSum() {
int sum = 0;
sum = num1 + num2;
return sum;
}
void printSum() {
// calculateSum will return sum value that will be printed here
cout <<"Sum = "<< calculateSum();
}
~ProblemSolution() {
cout << "\nDestructor is called " << endl;
};
};
int main() {
int a, b;
cout << "Enter a: ";
cin >> a;
cout << "Enter b: ";
cin >> b;
// Initiallizing object pointer of type ProblemSolution
ProblemSolution *objPtr = new ProblemSolution(a,b);
// printing Sum
objPtr->printSum();
// delete objPtr to relaease heap memory :important
delete objPtr;
return 0;
}
Explanation:
we will initialize a pointer "objPtr" and initallize the constructor by passing 2 values a and b followed by the keyword "new". the keyword "new" allocates memory in the heap. we can access class member functions using arrow "->". it is important to delete objPtr at the end of the program so that the heap memory can be freed to avoid memory leakage problems.
