A single die is rolled twice. the set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),
Maksim231197 [3]
<span>We need to find the rolls whose sum is greater than 10. By looking at the outcomes, we see that (5,6), (6,5), and (6,6) all have a sum greater than 10. Therefore, there are 3 chances to get a sum greater than 10. Since there are 36 chances overall, the probability of rolling greater than 10 are 3/36 = 1/12.</span>
Answer:
YET
Step-by-step explanation:
TO DECRYPT DKA USING THE CAESAR SHIFT CIPHER STARTING WITH 5 SHIFTS.
TO DO THIS DECRYPTION, WE'RE GOING TO LOOP THE ALPHABETS.
D = LOOPING THIS LETTER 5 TIMES, WE HAVE C - B - A - Z - Y.
SO, D IS DECRYPTED AS Y
GOING FURTHER, THE ENCRYPTION SHIFTS BY AN ADDITIONAL SPACE. THIS MEANS, IF THE FIRST "Y" WAS ENCRYPTED IN 5 SPACES TO GET D, AND AN ADDITIONAL SPACE WAS ADDED TO THE NEXT ALPHABET, IT BECOMES 6.
K IS THEN DECRYPTED AS
K = J - I - H - G - F - E
K IS DECRPYTED AS E
GOING FURTHER, THE NEXT WAS ENCRYPTED WITH AN ADDITIONAL SPACE EVEN MORE, SO, A IS DECRPYTED AS
A = Z - Y - X - W - V - U - T.
THUS, DKA IS DECRYPTED AS YET
Answer:We cant see it
Step-by-step explanation:
When adding fractions you need to get common denominators then you multiply too times bottom and then boom add and there you go
