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Cerrena [4.2K]
3 years ago
7

The following set of points are on the graph of a function: x,2,3,4,5,6,7 y,4,5,6,7,8,9 Which point would be on the inverse of t

his function? A) (-2,-4) B) (-5,-7) C) (7,5) D) (-7,-5)
Mathematics
1 answer:
stepladder [879]3 years ago
3 0
The answer would have to be C 7,5
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Alfonso runs 10 km at an average speed of x km/h.
puteri [66]

Step-by-step explanation:

Note that t = d/r where t is time, d is distance, and r is rate/speed.

We can come up with two equations with the information given and the equation:

t_1 hr = (10 km)/(x km/hr)

t_2 hr = (12 km)/(x - 1 km/hr)

<em>where t_1 is the time taken to run the 10km the first day and t_2 is the time taken to run the 12km the second day.</em>

We know that 30 minutes is 1/2 of an hour and that t_1 is 30 minutes less than t_2 (as stated in the question). Therefore, we can write:

t_1 = t_2 - 1/2

Substituting the values we derived:

(10 km)/(x km/hr) = (12 km)/(x - 1 km/hr) -1/2

Then we can evaluate by multiplying by 2x(x-1) on both sides:

20(x-1) = 24x - (x)(x-1)

20x - 20 = 24x - x^2 + x

x^2 -5x -20 = 0

And we are done.

I hope this helps! :)

6 0
3 years ago
B
zhuklara [117]

Answer:

90 degree is my guess please

4 0
3 years ago
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Karen already owns 3 hair bands, and additional hair bands are priced at 8 for a dollar. How much money does Karen need to spend
kiruha [24]

Answer:

Karen needs to spend $4.5 to buy new hair bands.

Step-by-step explanation:

Given:

Hair bands Karen have = 3

cost of 8 hair bands = $1

Total Hair bands she require = 39

Hence Number of of new hair bands require = Total Hair bands she require - Hair bands Karen have = 39 -3 = 36

we need to find how much money she need to spend to buy new hair bands.

cost of 8 hair bands = $1

Cost of 36 hair bands = money need to spend on hair bands

By using Unitary method we get;

Money spend on new hair bands = \frac{36}{8} = \$4.5

Hence,Karen needs to spend $4.5 to buy new hair bands.

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aniked [119]

Answer:

It should be 9+h+2

Step-by-step explanation:

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356÷3<br><img src="https://tex.z-dn.net/?f=%203%20%5Csqrt%7B333%7D%20" id="TexFormula1" title=" 3 \sqrt{333} " alt=" 3 \sqrt{333
Keith_Richards [23]
Oh you can use photo math for This
5 0
3 years ago
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