Answer: I helped LOL
Step-by-step explanation:
Problem 13
10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get
10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q
so we get the original expression again. Here 10 is the GCF of the two terms.
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Plug p = 1 and q = 2 into the factored form
10*(p+q) = 10*(1+2) = 10*(3) = 30
As a check, let's plug those p,q values into the original expression
10*p+10*q = 10*1+10*2 = 10+20 = 30
We get the same output of 30
Answer:
153.94 in²
Step-by-step explanation:
Answer:
x=-10, y=-20
Step-by-step explanation:
Since both 2x and 3x+10 equals y, they equal each other.
2x = 3x + 10
x = -10
Substitute -10 for x
2(-10) = y
y=-20
Answer:

General Formulas and Concepts:
<u>Algebra I</u>
Terms/Coefficients
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Quotient Rule]: ![\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5B%5Cfrac%7Bf%28x%29%7D%7Bg%28x%29%7D%20%5D%3D%5Cfrac%7Bg%28x%29f%27%28x%29-g%27%28x%29f%28x%29%7D%7Bg%5E2%28x%29%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>

<u>Step 2: Differentiate</u>
- Derivative Rule [Quotient Rule]:

- Basic Power Rule:

- Exponential Differentiation:

- Simplify:

- Rewrite:

- Factor:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation