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Sever21 [200]
3 years ago
5

Una maestra esta comprando lapices para su salon de clases. Si una docena de lapices cuesta $0.79 puede comprar lapices con $5?

Mathematics
1 answer:
NeX [460]3 years ago
5 0

Answer:

Cantidad total de lapices= 76

Step-by-step explanation:

Dada la siguiente información:

Costo por docena= $0.79

Presupuesto total= $5

<u>Para calcular la cantidad total de lapiceras que se pueden comprar con $5, debemos usar la siguiente formula:</u>

Cantidad total de lapices= presupuesto total / costo por docena

Cantidad total de lapices=  5 / 0.79

Cantidad total de lapices= 6.33

<u>Para ser mas exactos:</u>

0.33*12= 4

Cantidad total de lapices= 6*12 + 4

Cantidad total de lapices= 76

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Step-by-step explanation:

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lubasha [3.4K]

Answer: x\geq 13

Step-by-step explanation:

Given

The inequality is  2x-7\geq 19

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\dfrac{1}{2}\times 2x\geq 26\times \dfrac{1}{2}\\\\x\geq 13

the shaded region in the figure indicates the solution set.

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100-3y+4y-3y2 simplified btw I don't have a lot of points
erastova [34]

Answer:

-3y^2 + y + 100

Step-by-step explanation:

Combine like terms.

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Add "y" back into the equation.

-3y^2 + y + 100

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I hope this helped!

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3 years ago
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the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years​
Yuliya22 [10]

Answer:  125 g

<u>Step-by-step explanation:</u>

A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k

\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125

8 0
4 years ago
A right-angled triangle has sides of lengths (x+5)cm, (x-3)cm and 9cm. Calculate the value of x
Arturiano [62]

Answer:

x=4.0625 cm

Step-by-step explanation:

The Pythagorean theorem states that the square of the hypotenuse of a right triangle equals the sum of the squares of the two legs.

Not knowing which is the hypotenuse, lets assume that (x+5)cm is the hypotenuse:

(x+5)^2= 9^2+(x-3)^2

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x^2+10x+25=81+x^2-6x+9

16x=65

x=4.0625

Checking:

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82.1289=82.1289

6 0
3 years ago
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