Cm^3 = mL
1.11 g/cm^3 = 1.11 g/mL
Density (g/mL) multiplied by volume (mL) will give us the mass (g)
1.11 g/mL * 385 mL = 427.35 g
And since we have 3 significant figures, we have 427. g.
The lines occurring in an emission spectrum are all electromagnetic waves, which means that their speed in a vacuum is
3 x 10⁸ m/s
We can use the equation,
v = fλ
which relates the velocity of a wave to the frequency and wavelength. Substituting values,
3 x 10⁸ = f * 434 x 10⁻⁹
f = 6.91 x 10¹⁴ Hz
The frequency of the wave will be 6.91 x 10¹⁴ oscillations per second.
Answer:
The process describes the source of energy of the Sun such that it shines as a result of nuclear fusion of hydrogen taking place.
Explanation:
The Sun generates energy by hydrogen within the Sun undergoing nuclear fusion to form helium.
Nuclear fusion reaction involves combining of two or more atomic nuclei to produce one or more completely different atomic nuclei as well as protons or neutrons, with a loss or gain of mass and the release or absorption of energy.
The process whereby four hydrogen atoms combine to form one helium atom with a mass deficit, which is accounted for by the release of energy, result in the high intense light of the Sun.
the Percentage yield for the reaction = 48.8%
What is Percentage yield ?
The % ratio of the theoretical yield to the actual yield is known as the percent yield. It is calculated as the theoretical yield multiplied by 100% divided by the experimental yield. The percent yield is 100% if the theoretical and actual yields are equal. Because the real yield is frequently lower than the theoretical value, percent yield is typically lower than 100%. This may be due to incomplete or conflicting reactions or sample loss during recovery. If the percent yield is more than 100%, more sample than expected was retrieved from the reaction.
4 P + 3 O2 = P4O6
moles P = 75.3 g / 30.9738 g/mol= 2.43
moles O2 required = 2.43 x 3 / 4=1.82
actual moles O2 = 38.7 g /32 g/mol=1.21 so O2 is the limiting reactant
theoretical moles P4O6 = 1.21 / 3=0.403
theoretical mass P4O6 = 0.403 mol x 219.895 g/mol=88.6 g
% yield = 43.3 x 100/ 88.6 = 48.8 %
the Percentage yield for the reaction = 48.8%
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