Answer:
25
Explanation:
explain no need it is perfect
Answer:25.3 g of KNO₃ contain 0.25 moles.
Explanation:
Answer:
The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.
Explanation:
..[1]
..[2]
..[3]
..[4]
Using Hess's law:
Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
2 × [4] = [2]- (3 ) × [1] - (2) × [3]
![2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}](https://tex.z-dn.net/?f=2%5Ctimes%20%5CDelta%20H%5Eo_%7B4%7D%3D%5CDelta%20H%5Eo_%7B2%7D%20-3%5Ctimes%20%5CDelta%20H%5Eo_%7B1%7D-2%5Ctimes%20%5CDelta%20H%5Eo_%7B3%7D)
![2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol](https://tex.z-dn.net/?f=2%5Ctimes%20%5CDelta%20H%5Eo_%7B4%7D%3D498.4%20kJ%2Fmol-3%5Ctimes%20142.7%20kJ%2Fmol-2%5Ctimes%20-200%20kJ%2Fmol)
![2\times \Delta H^o_{4}=470.3 kJ/mol](https://tex.z-dn.net/?f=2%5Ctimes%20%5CDelta%20H%5Eo_%7B4%7D%3D470.3%20kJ%2Fmol)
![\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7B4%7D%3D%5Cfrac%7B470.3%20kJ%2Fmol%7D%7B2%7D%3D235.15%20kJ%2Fmol)
The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.
I think the answer is C. 02
The temperature change is 23 °C.
<em>q = mC</em>Δ<em>T</em>
Δ<em>T</em> = <em>q</em>/(<em>mC</em>)
<em>m</em> = 355 g
∴ Δ<em>T</em> = (34 000 J)/(355 g × 4.184 J·°C⁻¹g⁻¹) = 23 °C
<em>Note</em>: The answer can have only <em>two significant figures</em> because that is all you gave for the amount of heat absorbed.