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Harrizon [31]
2 years ago
5

a sample of helium occupies a volume of 101.2 mL at a pressure of 790 mmHg. at what pressure would the volume be 120 mL?

Chemistry
1 answer:
AveGali [126]2 years ago
6 0

Answer : The final pressure will be, 666.2 mmHg

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure = 790 mmHg

P_2 = final pressure = ?

V_1 = initial volume = 101.2 mL

V_2 = final volume = 120 mL

Now put all the given values in the above equation, we get:

790mmHg\times 101.2mL=P_2\times 120mL

P_2=666.2mmHg

Therefore, the final pressure will be, 666.2 mmHg

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Answer:

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Explanation:

Given data:

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Mole fraction of nitrogen:

Mole fraction of nitrogen = moles of nitrogen / total number of moles

Mole fraction of nitrogen =   0.35  mol / 0.676 mol

Mole fraction of nitrogen =   0.52

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