Answer:
x=2; the extraneous root x=42.
All the details are in the attached picture, the answer is marked with red colour.
In an arithmetic sequence:
Tn=t₁+(n-1)d
t₄=t₁+(4-1)d=t₁+3d
t₅=t₁+(5-1)d=t₁+4d
t₆=t₁+(6-1)d=t₁+5d
t₄+t₅+t₆=(t₁+3d) +(t₁+4d)+(t₁+5d)=3t₁+12d
Therefore:
3t₁+12d=300 (1)
t₁₅=t₁+(15-1)d=t₁+14d
t₁₆=t₁+(16-1)d=t₁+15d
t₁₇=t₁+(17-1)d=t₁+16d
t₁₅+t₁₆+t₁₇=(t₁+14d)+(t₁+15d)+(t₁+16d)=3t₁+45d
Therefore:
3t₁+45d=201 (2)
With the equations (1) and (2) we make an system of equations:
3t₁+12d=300
3t₁+45d=201
we can solve this system of equations by reduction method.
3t₁+12d=300
-(3t₁+45d=201)
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-33d=99 ⇒d=99/-33=-3
3t₁+12d=300
3t₁+12(-3)=300
3t₁-36=300
3t₁=300+36
3t₁=336
t₁=336/3
t₁=112
Threfore:
Tn=112+(n-1)(-3)
Tn=112-3n+3
Tn=115-3n
Now, we calculate T₁₈:
T₁₈=115-3(18)=115-54=61
Answer: T₁₈=61
Because if you rotate an object 360 degrees it’s like the object never moved because the object would still be in the same spot as if you didn’t move it
Answer:
Least number of bus require for trip = 5 buses (Approx)
Step-by-step explanation:
Given:
Total number of classes = 9
Number of student in each class = 25
Number of teacher = 4
Number of chaperones = Double of teacher
Bus hold = 45 people
Find:
Least number of bus require for trip
Computation:
Total number of student = 9 × 25
Total number of student = 225
Number of chaperones = 4 × 2
Number of chaperones = 8
Total people = 225 + 8 + 4
Total people = 237
Least number of bus require for trip = Total people / Bus hold
Least number of bus require for trip = 237 / 45
Least number of bus require for trip = 5.266
Least number of bus require for trip = 5 buses (Approx)
