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anygoal [31]
4 years ago
6

Two machines are used for filling plastic bottles with a net volume of 16.0 ounces. The fill volume can be assumed normal,with sta

ndard deviation 01 = 0.020 and 02 = 0.025 ounces. A member of the quality engineering staff suspects that bothmachines fill to the same mean net volume, whether or not this volume is 16.0 ounces. A random sample of 10 bottles istaken from the output of each machine.16.03 16.01 16.02 16.0316.04 15.96 15.97 16.0416.05 15.98 15.96 16.0216.05 16.02 16.01 16.0116.02 15.99 15.99 16.00(a) Do you think the engineer is correct? Use the P-value approach.(b) If a = 0.05, what is the power of the test in part (a) for a true difference in means of 0.04?(c) Find a 95% Cl on the difference in means. Provide a practical interpretation of this interval.(d) Assuming equal sample sizes, what sample size should be used to ensure that B = 0.01 ifthe true difference in means is0.04? Assume that a = 0.05.
Mathematics
1 answer:
Mademuasel [1]4 years ago
8 0
It’s 5.05. Is the answer to theis propblem
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Solve for x. -14 = -7/3x Simplify your answer as much as possible. Plz Plz help quick!! (:
omeli [17]

x = 32.7

-14 = 7/3x

-14 * 7 = 3x

98 = 3x

98/3 = 3x/3

32.666667= x

32.7 = x

Hope that helped :)

7 0
3 years ago
Read 2 more answers
A ( 2, -2)<br> B ( 3, -5)<br> C (-5, 3)<br> D (-2, 2)<br> Help please
chubhunter [2.5K]

Answer:

A. (2, -2)

Step-by-step explanation:

if you find the median between (-1,3) and (5,-7) you get (2,-2).

7 0
3 years ago
Read 2 more answers
What is 5(x + 4) + 16
trasher [3.6K]

Answer:

5x+36

Step-by-step explanation:

7 0
3 years ago
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angle 1 and an angle that measures 50° are supplementary another angle that measures 50 degrees and angle 3 are supplementary sh
MakcuM [25]

∠1 ≅∠3 = 130º

1) Gathering the data, accordingly to what's been told we can write:

∠1 + ∠50º = 180º <em>Definition of two supplementary angles</em>

∠50 +∠3 = 180º

2) Then we can evaluate:

∠1 + ∠50º = 180º <em>Subtract ∠50º from both sides</em>

∠1 = 180º -50º

∠1 = 130º

∠50 +∠3 = 180º

∠3 = 180º-50º

∠3 = 130º

3) Hence ∠1 ≅∠3 = 130º because the definition of supplementary angles is the same.

8 0
1 year ago
Suppose x is a normally distributed random variable with μ = 50 and Ϭ = 3. Find a value of the random variable, call it x0, such
mihalych1998 [28]

Answer:

Step-by-step explanation:

Given that X is N(50,3)

So whenever we want score for x, we can convert this to Z and use std normal distribution table.

The formula for conversion is

Z = \frac{x-50}{3}

Using this we can find out the corresponding scores

a) P(X\leq X_0) = 0.8413

Z value = 1 and hence

X_o = 50+1(3) = 53\\

b) P(x > x0) = 0.25

z=0.5-0.0987=0.4013\\X0= 50+3(0.4013)\\= 51.2039

c) P(x > x0) = 0.95\\z=2\\X_0 = 50+6 =56

d) P(41 ≤ x < x0) = 0.8630 \\P(-3 ≤ Z

e) 10th percentile is 50-1.28(3) =46.16

f) This is 99th percentile

=50+2.33(3)\\= 56.69

5 0
3 years ago
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