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lara31 [8.8K]
2 years ago
10

What is the answer i'll give brainly

Mathematics
1 answer:
egoroff_w [7]2 years ago
8 0

Answer:

c = -3

Step-by-step explanation:

Multiply all terms by the same value to eliminate fraction denominators

4(-2)=4*\frac{-c-11}{4}

Cancel multiplied terms that are in the denominator

4(-2)=-c-11

Multiply the numbers

-8=-c-11

Add 11 to both sides of the equation

-8+11=-c-11+11

Simplify

3=-c

Divide both sides of the equation by the same term

\frac{3}{-1}=\frac{-c}{-1}

Simplify

c=-3

[RevyBreeze]

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Problem 2:
kifflom [539]

Answer:

The answers to the questions about problem 2 are:

  1. The fraction of the length after Priya stops two times is 3/4.
  2. The fraction of the length after Priya stops four times is 15/16.
  3. Priya will never reach the end of the hallway.

Step-by-step explanation:

The explanation about each answer is below:

1. In the first stop, Priya has walked half of the total length, and there would still be half the hallway, however, when she stops the second time, she has walked the half of the half, I mean:

\frac{1}{2}/2=\frac{1}{4}

If you add the two values you obtain the total distance traveled by Priya:

\frac{1}{2}+\frac{1}{4}= \frac{3}{4}

And the distance traveled in two stops is 3/4 of the total length of the hallway.

2. With four stops the system is the same, we know with two stops Priya travels 3/4 of the hallway, now with the third stop, she will travel half of the remaining distance:

\frac{1}{4}/2=\frac{1}{8}

And in the fourth stop she will travel half of the remaining, I mean:

\frac{1}{8}/2=\frac{1}{16}

Now, we add all the values of the distances obtained:

\frac{3}{4}+\frac{1}{8}+\frac{1}{16}= \frac{15}{16}

So, the distance traveled by Priya in the fourth stop is 15/16 of the total length of the hallway.

3. How we know, the numbers are infinite, in the same forms the distances, by this reason, how the problem says that Priya walks just half of the distance, she will never reach the end because despite she has very near of the end, she will continue walking just half and ever smaller distances.

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3 years ago
Do you need to restrict the domain of hte inverse of a cubic function
aalyn [17]
I dont believe so but im not 100% sure i hoped i helped
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3 years ago
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