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lara31 [8.8K]
2 years ago
10

What is the answer i'll give brainly

Mathematics
1 answer:
egoroff_w [7]2 years ago
8 0

Answer:

c = -3

Step-by-step explanation:

Multiply all terms by the same value to eliminate fraction denominators

4(-2)=4*\frac{-c-11}{4}

Cancel multiplied terms that are in the denominator

4(-2)=-c-11

Multiply the numbers

-8=-c-11

Add 11 to both sides of the equation

-8+11=-c-11+11

Simplify

3=-c

Divide both sides of the equation by the same term

\frac{3}{-1}=\frac{-c}{-1}

Simplify

c=-3

[RevyBreeze]

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a broker gets rs 20000 as commission from sale of a piece of land which costs rs 8000000. Find the rate of commission.​
Airida [17]

Answer:

0.25%

Step-by-step explanation:

Rate of commission

= (commission*100)/cost of land

=( 20000*100)/8000000

= 2000000/8000000

=2/8

= 0.25%

3 0
2 years ago
How to get 813 with exponents parentheses in three different operations
LenKa [72]

Answer:

813 = 800 + 10 + 3 = (8 \times 10^{2} ) + ( 1\times 10^1 ) + ( 3 \times 10^0 )  

Step-by-step explanation:

i) 813 = 800 + 10 + 3 = (8 \times 10^{2} ) + ( 1\times 10^1 ) + ( 3 \times 10^0 )  

4 0
2 years ago
How would I do the steps to solve this?
allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

R(p) = -10p^2+800p

Taking derivative wrt p

\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\

Now putting R'(p) = 0

-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000

The maximum revenue is 16000 dollars (at p = 40)

3 0
2 years ago
The measure of the exterior angle of the triangle is
Nookie1986 [14]

Answer:

jsjsjsisusbbdbdjsjcjdjsjjsjsjsjsjdjxjx

4 0
2 years ago
What are the number of integral solutions of the equation 2x+2y+z=20 such that x>=0 , y>=0 , z>=0?
zaharov [31]
2x+2y+z=20\\
z=\dfrac{20}{2x+2y}\\
z=\dfrac{10}{x+y}

Now, for z to be an integer, the sum x+y must be a divisor of 10. 
It has to be a positive divisor since z≥0. Also x≠y.

x+y=1 \\
x=1-y\\

x≥0 and y≥0 so y can be equal to either 0 or 1. There are 2 solution in this case.

x+y=2\\
x=2-y\\
In this case, y can be equal to 0,1, or 2, but for y=1 ⇒ x=1, so there are two solutions.

x+y=5\\
x=5-y
y can be 0,1,2,3,4 or 5 - 6 solutions

x+y=10\\
x=10-y
y can be 0,1,2,3,4,5,6,7,8,9,10, but for y=5 ⇒ x=5, so 10 solutions.

2+2+6+10=20 solutions in total.
6 0
3 years ago
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