Question

Use your table to work out what fraction of the fish are 50cm or more in length

Answer 1

Answer:

very very

Step-by-step explanation:

⟼sinA−cosAsinA+cosA+sinA+cosAsinA−cosA

Let,

sinA be a

cosA be b

⟼ \frac{a + b}{a - b} + \frac{a - b}{a + b}⟼a−ba+b+a+ba−b

⟼ \frac{(a + b)^{2} + (a - b) ^{2}}{(a + b)(a - b)}⟼(a+b)(a−b)(a+b)2+(a−b)2

⟼ \frac{2( {a}^{2} \: {b}^{2} ) }{ {a}^{2} - {b}^{2} }⟼a2−b22(a2b2)

Putting values

⟼ \frac{2 \sin^{2} A \: + { \cos }^{2} A }{ { \sin }^{2}A- { \cos }^{2}A }⟼sin2A−cos2A2sin2A+cos2A

⟼ \frac{2}{ { \sin}^{2} A - \cos^{2}A}⟼sin2A−cos2A2

Hope it helps you!!

#IndianMurga

Answer 2

We need to find frequency in the region.

$\\ \sf\longmapsto 50\leqslant l$

We should calculate in it frequencies of below

$\\ \sf\longmapsto 50\leqslant l$

$\\ \sf\longmapsto 60\leqslant l$

$\\ \sf\longmapsto 80\leqslant l$

$\\ \sf\longmapsto 100\leqslant l$

Hence

total frequency:-

$\\ \sf\longmapsto 8+b+c+d$