Perimeter of triangle ABC is 20 units.
Solution:
The image for reference is attached below.
Given AE = 2, BD = 5 and CF = 3
Two tangents drawn from an external point to a circle are equal in length.
AD = AE, BF = BD and CE = CF
Therefore, AD = 2, BF = 5 and CE = 3
Perimeter of the triangle = sum of the three sides
Perimeter of triangle ABC = AB + BC + CA
= AD + BD + BF + CF + CE + AE
= 2 + 5 + 5 + 3 + 3 + 2
= 20
Hence, perimeter of triangle ABC is 20 units.
Answer:
There are none.
Step-by-step explanation:
<u>No calculus involved:</u>
The line, in slope-intercept form, has equation , ie is always decreasing (easy to spot applying the definition)
Meanwhile, is always increasing over its domain.
At no point the tangent will be decreasing.
<u>Let's use calculus</u>
We are to solve the equation which has no real solutions.
