Answer:
The best point of estimate for the true mean is:

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.
Step-by-step explanation:
Information given
represent the sample mean for the late time for a flight
population mean
represent the population deviation
n=76 represent the sample size
Confidence interval
The best point of estimate for the true mean is:

The confidence interval for the true mean is given by:
(1)
The Confidence level given is 0.95 or 95%, th significance would be
and
. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got
Replacing we got:
Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.
Answer: w, 0
Step-by-step explanation:
you can see that G has the same distance from 0 as E does, so you can just take away the - sign. It hasn't left the line so its still 0.
Therefore, the total costs for year 1 will be $2,240, for year 2 they will be $2,040, and for year 3 they will be $2,120.
<h3><u /></h3><h3><u>Costs</u></h3>
Given that one of your company's salesmen estimates he will drive 20,000 miles this year and each of the next two years, and as the service manager for the company's fleet of six-cylinder compact automobiles, you are asked to determine the total costs for each of the three years, to determine said cost, the following calculation must be made:
- Year 1:
- 20000 x 0.112 = X
- 2,240 = X
- Year 2:
- 20000 x 0.102 = X
- 2,040 = X
- Year 3:
- 20000 x 0.106 = X
- 2,120 = X
Therefore, the total costs for year 1 will be $2,240, for year 2 they will be $2,040, and for year 3 they will be $2,120.
Learn more about costs in brainly.com/question/4557688
Answer:
the answer to the question is C
The probability of randomly drawing either a red marble or a green marble is 80%
The probability of drawing a green marble is the same as the probability of drawing either a red or a blue marble.
3 out of 4
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