The dimensions of the rectangular( length and width) are 14m and 15m.
Here we have to find the dimension of the length and width.
Data given:
Fencing = 58m
Area = 210 m²
Let us assume the length be x
By this, we get the width as:
width = 58 - 2x / 2
= 29-x
As the area is 210 m²
The formula to find the area of the rectangular is:
Area = length ×width
210 = x ( 29 -x)
x² - 29 x + 210 = 0
Formula to find the value of x from the quadratic equation:
x = -b ±![\sqrt{b^{2} - 4ac }](https://tex.z-dn.net/?f=%5Csqrt%7Bb%5E%7B2%7D%20-%204ac%20%7D)
For the general equation ax² + bx + c =0
As the equation is:
x² - 29x + 210 = 0
a = -1
b = -29
c = -210
So,
x = 29 ±
/ 2(-1)
= 29± 1/-2
= 14, 15
29 - x = 15, 14 (for the value of x = 14 and 15 respectively)
Therefore the dimensions are 14m and 15m.
To know more about the rectangular refer to the link given below:
brainly.com/question/25292087
#SPJ4
80y hope this helps and goodd luckkk :)
Answer:
willie has 30 friends
Step-by-step explanation:
subtract 8 from 98 = 90 divide 90 by 3 and it gives you the answer of 30 and thats how many friends willie has.
Answer:
that is you my question is wrong for me
The volume of this box can be given by
V=(12-2x)(10-2x)(x), or in simplified form, V=120x-44x²+4x³.
To find the volume of the box, we would subtract x from both ends of the length, so 12-2x. We also subtract x from both ends of the width, so 10-2x. The height of the box is given by the x amount that is cut out from the box. Volume of a box is given by length*width*height.