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timofeeve [1]
3 years ago
6

What are the dimensions of the new room, in inches, on the blueprint? What will the dimensions of the new room be, in feet, in t

he new house?
in the attachment, the answers on the bottom are incorrect. please help me I do not understand what I am doing wrong.
info needed: q'(3.75,1.25) r'(8.75,1.25) s'(8.75,7.5) t'(3.75,7.5)
(48x,48y)

Mathematics
1 answer:
Ainat [17]3 years ago
3 0

Answer:

Lay the proper scale next to the item on the drawing and take the measurement. The scale will translate for you. As an example, a 1/4 inch = 1 foot architect scale will have markings that increase by 1 foot every 1/4 inch; a 4 foot wall is represented by a 1-inch length, if measured with a conventional ruler.

Step-by-step explanation:

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What is the solution for the following system of equations?<br><br>5x + 7y = 3<br><br>2x + 3y = 1
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<span>A) 5x + 7y = 3
B) 2x + 3y = 1

Multiplying Equation B by -2.5
</span><span>B) -5x -7.5y = -2.5 Then adding this to Equation A)
A) 5x + 7y = 3</span>

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Read 2 more answers
Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)
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Use the distance formula.

\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}

 
Points S and W.
\sqrt{(3)^2 + (2)^2}

\sqrt{9+4}

\sqrt{13}

~3.6

Points S and T
\sqrt{(3 - 0)^2 + (-2 - 0)^2}

\sqrt{(3)^2 + (-2)^2}

\sqrt{9+4}

\sqrt{13}

~3.6

Points T and U
\sqrt{(3 - 2)^2 + (-2 + 5)^2}

\sqrt{(1)^2 + (3)^2}

\sqrt{1+9}

\sqrt{10}

~3.1

Points U and V
\sqrt{(2+2)^2 + (-5 + 5)^2}

\sqrt{(4)^2 + (0)^2}

\sqrt{16}

~4

Points V and W
\sqrt{(-2+3)^2 + (-5 + 2)^2}

\sqrt{(1)^2 + (-3)^2}

\sqrt{2+9}

\sqrt{11}

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17
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