What we have so far:
INITIAL CASH AMOUNT IN THE BANK: USD3,000
ANNUAL INCREASE OF THE CASH AMOUNT IN THE BANK: 10%
YEARS THE CASH STAYED IN THE BANK: 2 years.
AMOUNT WITHDRAWN AT THE END OF YEAR 1: USD1,206
AMOUNT WITHDRAWN AT THE END OF YEAR 2: USD1,206
First, we need to solve for YEAR 1:
FOR YEAR 1:
Initial Deposit * Annual Increase Rate = Annual Increase
3,000 * 0.10 = Year 1's Annual Increase
Year 1's Annual Increase = USD300
∴The YEAR 1'S ANNUAL INCREASE IS USD300.
∴The NEW AMOUNT is now USD3,300.
BUT NOT SO FAST! After the year, you took out USD1,206.
New Amount - USD1,206 = Year 1 Amount
3,300 - 1,206 = Year 1 Amount
Year 1 Amount = USD2094
∴The YEAR 1 AMOUNT which will carry over to YEAR 2 is USD2094.
Now, let us solve for the REMAINING BALANCE.
FOR YEAR 2's Annual Increase:
YEAR 1 AMOUNT * Annual Increase = Year 2's Annual Increase
2094*0.10 = Year 2's Annual Increase
Year 2's Annual Increase = USD209.4
∴The YEAR 1'S ANNUAL INCREASE IS USD209.4.
∴The NEW AMOUNT is now USD2,303.4.
But you took out USD1,206
USD2,303.4 - USD1,206 = Remaining Balance
Remaining Balance = USD1097.4
∴The Answer is: USD1097.4
Q=54
You subtract 7 from 61
In this question, it is given that
A certain bacteria culture grows at a rate of 18% everyday. There are currently 420 bacteria.
And we have to find number of bacterias on day *.
For that we use the following formula
Substituting these values in the formula, we will get
THerefore on day 8, number of bacterias are 1579.
Answer:
Lisa can buy 5 pounds of tomatoes.
Step-by-step explanation:
Given that Lisa has $ 7.80 to spend on some tomatoes and a loaf of bread, and tomatoes cost $ 1.20 per pound, and a loaf of bread costs $ 1.80, to determine how many pounds of tomatoes she can buy, the following calculation must be performed:
1.20X + 1.80 = 7.80
1.20X = 7.80 - 1.80
X = 6 / 1.20
X = 5
So Lisa can buy 5 pounds of tomatoes.
50+2x=100
-50 -50(subtract 50 from both sides)
2x=50 (divide both sides by 2)
x=25
