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Mice21 [21]
3 years ago
9

When constructing a line perpendicular to XY through point S, on which point should the

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

Point S or, option B.

Step-by-step explanation:

Canvas test

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Given the linear equation 5x+3y-9=0. Write another linear equation in two variables such that the geometrical representation of
just olya [345]

Answer:5x+3y+1=0

Step-by-step explanation:

Given

The linear equation is 5x+3y-9=0

The other linear equation parallel to the given line can be represented by

5x+3y+c=0

Here, c can take any value . for example c=1, line becomes

\Rightarrow 5x+3y+1=0

8 0
3 years ago
-32x + 45 – 7 (2x – 9) = 101
Evgesh-ka [11]

Answer:

x =  \frac{7}{46}

Step-by-step explanation:

-32x+45-7(2x-9)=101

parenthesis first

-32x+45-14x+63=101

just combine like terms

-46x+108=101

minus 108 both sides

-46x= -7

answer is x 7 over 46

5 0
3 years ago
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One side of a square flower bed is 8 feet long. how many plants are needed if they are to be spaced 8 inches apart around the ou
Sloan [31]

The side is 8 feet = 8*12 inches = 96 inches

Plants are needed if they are to be spaced 8 inches apart around the outside of the bed

96/8 = 12 ... so we need 12 plants on each side, please note it is including the corners.

If we not incluse corner, the flowers will be 10 each side.

Means total flower : 10 * 4 (each side) + 4(corner)

The total needed is 44 plants. : Answer

Hope that will help :)

4 0
3 years ago
A motel rents double rooms at $34 per day and single rooms at $27 per day. If 26 rooms were rented one day for a total of $807,
torisob [31]

Let, number of double rooms and single rooms are d and s.

d + s = 26     ....1 )

Hotel rents double rooms at $34 per day and single rooms at $27 per day.

34d + 27s = 807   ....2)

Solving equation 1 and 2, we get :

34( 26 - s ) + 27s = 807

884 - 34s + 27s = 807

7s = 77

s = 11

And d = 26 - 11 = 15

Therefore, number of double rooms and single rooms are 15 and 11.

Hence, this is the required solution.

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Ctext%7BQuestion%7D%7D%20%3A%20" id="TexFormula1" title=" \underline{ \
Oliga [24]

Answer:

Part A)

The height of the water level in the rectangular vessel is 2 centimeters.

Part B)

4000 cubic centimeters or 4 liters of water.

Step-by-step explanation:

We are given a cubical vessel that has side lengths of 10cm. The vessel is completely filled with water.

Therefore, the total volume of water in the cubical vessel is:

V_{C}=(10)^3=1000\text{ cm}^3

This volume is poured into a rectangular vessel that has a length of 25cm, breadth of 20cm, and a height of 10cm.

Therefore, if the water level is h centimeters, then the volume of the rectangular vessel is:

V_R=h(25)(20)=500h\text{ cm}^3

Since the cubical vessel has 1000 cubic centimeters of water, this means that when we pour the water from the cubical vessel into the rectangular vessel, the volume of the rectangular vessel will also be 1000 cubic centimeters. Hence:

500h=1000

Therefore:

h=2

So, the height of the water level in the rectangular vessel is 2 centimeters.

To find how how much more water is needed to completely fill the rectangular vessel, we can find the maximum volume of the rectangular vessel and then subtract the volume already in there (1000 cubic centimeters) from the maximum volume.

The maximum value of the rectangular vessel is given by :

A_{R_M}=20(25)(10)=5000 \text{ cm}^3

Since we already have 1000 cubic centimeters of water in the vessel, this means that in order to fill the rectangular vessel, we will need an additional:

(5000-1000)\text{ cm}^3=4000\text{ cm}^3

Sincer 1000 cubic centimeters is 1 liter, this means that we will need four more liters of water in order to fill the rectangular vessel.

3 0
3 years ago
Read 2 more answers
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