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2 years ago

List the common multiple of 42 and 14 . Help plzzzz

Mathematics

1 answer:

Alborosie2 years ago

3 0

The answer is 42,84,126 and so on.(you keep on adding 42)

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Wich tool is used to measure the lengths of segments when preforming a formal geometric construction

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A ruler as that is the only option that can measure segments

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3 years ago

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2 years ago

Item 16 A sphere has a radius of 8 centimeters. A second sphere has a radius of 2 centimeters. What is the difference of the vol

Zigmanuir [339]

Answer:

$672\pi \text{ cm}^3$ .

Step-by-step explanation:

We have been given that a sphere has a radius of 8 centimeters. A second sphere has a radius of 2 centimeters. We are asked to find the difference of the volumes of the spheres.

We will use volume formula of sphere to solve our given problem.

$\text{Volume of sphere}=\frac{4}{3}\pi r^3$ , where r is radius of sphere.

The difference of volumes would be volume of larger sphere minus volume of smaller sphere.

$\text{Difference of volumes}=\frac{4}{3}\pi(\text{8 cm})^3-\frac{4}{3}\pi(\text{2 cm})^3$

$\text{Difference of volumes}=\frac{4}{3}\pi(512)\text{ cm}^3-\frac{4}{3}\pi(8)\text{ cm}^3$

$\text{Difference of volumes}=\frac{4}{3}\pi(512-8)\text{ cm}^3$

$\text{Difference of volumes}=4\pi(168)\text{ cm}^3$

$\text{Difference of volumes}=672\pi\text{ cm}^3$

Therefore, the difference between volumes of the spheres is $672\pi \text{ cm}^3$ .

3 0

3 years ago

Can anyone please help me with this ?

djverab [1.8K]

Answer:

The distance from point A to the top of the building is 5 $\sqrt{2}$ feet

The Height of the Skyscraper is 5 feet

Step-by-step explanation:

Given

Let Top point of building be point C

Also Let Base of the building be point B

Distance from point A to base B of the building AB= 5 feet

∴ It makes a Right angle triangle

Also ∠ACB = 45°

Also tan 45° = 1

Now tan ∠ACB = $\frac{AB}{BC}$

∴ AB= BC =5 feet

The Height of the Skyscraper is 5 feet

Now Triangle ABC is right angle triangle with right angled at B

So by Pythagoras theorem

AC= $\sqrt{AB^2+BC^2}=\sqrt{5^2+5^2} =\sqrt{50} =\sqrt{25\times2} =\sqrt{5^2\times2}=5\sqrt{2}$

The distance from point A to the top of the building is 5 $\sqrt{2}$ feet

5 0

3 years ago

Read 2 more answers

Y=x^2+5x-8 to factored form

almond37 [142]

Answer:

Factor and set each factor equal to zero. Y=x2+5x−8

Step-by-step explanation:

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2 years ago