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Alexus [3.1K]
2 years ago
8

How to find surface area of a triangular prism

Mathematics
1 answer:
Ugo [173]2 years ago
8 0

Answer:if there is numbers then you would multiply then or divide them to find it

Step-by-step explanation:

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Solve for x: 2/3=8/x+6
Tresset [83]

Answer:

x = 6

Step-by-step explanation:

2/3=8/x+6

Using cross products

2 * (x+6) = 3*8

2(x+6) = 24

Divide by 2

x+6 =12

Subtract 6

x = 6

8 0
2 years ago
Read 2 more answers
What is a reasonable estimate for the solution? O (1,-3/4) O (-3/4,1) O (-1,3/4) O (3/4,-1)​
Zina [86]

Answer:

See Explanation

Step-by-step explanation:

Your question is incomplete, as the equations or graph or table(s) were not given.

However, I'll give a general way of solving this.

Take for instance, the equations are:

y = \frac{4}{3}x - 1

y = \frac{2}{3}x - \frac{1}{2}

To do this, we start by equating both equations.

y = y

i.e.

\frac{4}{3}x - 1= \frac{2}{3}x - \frac{1}{2}

Collect Like Terms

\frac{4}{3}x - \frac{2}{3}x= 1 - \frac{1}{2}

Take LCM

\frac{4x- 2x}{3}= \frac{2 - 1}{2}

\frac{2x}{3}= \frac{1}{2}

Cross Multiply

2x * 2 = 3 * 1

4x = 3

Make x the subject

x = \frac{3}{4}

Substitute 3/4 for x in y = \frac{4}{3}x - 1

y = \frac{4}{3} * \frac{3}{4} - 1

y = 1 - 1

y = 0

Hence:

(x,y) = (\frac{3}{4},0)

6 0
2 years ago
What is 5 raised to the 5th power?
Roman55 [17]
 Five raised to the fifth power 5^5   5*5*5*5*5 = 3,125
8 0
3 years ago
Read 2 more answers
Select the correct answer.
Alla [95]

Answer:

Step-by-step explanation:

7 0
2 years ago
Suppose a population grows according to the logistic equation but is subject to a constant total harvest rate of H. If N(t) is t
Elenna [48]

Answer:

a) Equilibrium point : [ 947, 53 ]

b) N = 947 is stable equilibrium, N = 53  is unstable equilibrium

c) N0, the population will not go extinct

Step-by-step explanation:

a)

Given that;

r = 2, k = 1000, H = 100

dN/dT = R(1 - N/k)N - H

so we substitute

dN/dt = 2( 1 - N/1000)N - 100

now for equilibrium solution, dN/dt = 0

so

2( 1 - N/1000)N - 100 = 0

((1000 - N)/1000)N = 50

N^2 - 1000N + 50000 = 0

N = 1000 ± √(-1000)² - 4(1)(50000)) / 2(1)

N = 947.213 OR 52.786

approximately

N = 947 OR 53

Therefore Equilibrium point : [ 947, 53 ]

b)

g(N) = 2( 1 - N/1000)N - 100

= 2N - N²/500 - 100

g'(N) = 2 - N/250

SO AT 947

g'(N) = g'(947) =  2 - 947/250 = -1.788 which is less than (<) 0

so N = 947 is stable equilibrium

now AT 53

g'(N) = g"(53) = 2 - 53/250 = 1.788 which is greater than (>) 0

so N = 53  is unstable equilibrium

The capacity k=1000

If the population is less than 53 then the population will become extinct but since the capacity is equal to 1000 then the population will not go extinct.

6 0
3 years ago
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