Answer: -35
Step-by-step explanation:
You can check it by multiplying -3 and -35 you should get 105
Answer: 3 × 10^4
Step-by-step explanation:
9x10^2 is how many times as much as 3x10^-2?
9 × 10^2 = 9 × 100 = 900
3 × 10^-2 = 3 × 0.01 = 0.03
We then divide, this will be:
= 900/0.03
= 30000
This can be represented as:
30000 = 3 × 10^4
First you have to divide then you have to multiply your answer with the original answer then
For the fourth term replace n by 4:-
4th term = -6 + (4 - 1)(1/5)
= -6 + 3/5 = -5 2/5 ( or -27/5) answer
10th term = -6 + (10 - 1)(1/5)
= - 6 + 9/5 = -4 1/5 or -21/5 answer
Using the Factor Theorem, it is found that yes, it is possible for a sixth degree polynomial function with integer coefficients to have no real zeroes, as they can have three complex-conjugate pairs.
<h3>What is the Factor Theorem?</h3>
The Factor Theorem states that a polynomial function with roots
is given by:
![f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)](https://tex.z-dn.net/?f=f%28x%29%20%3D%20a%28x%20-%20x_1%29%28x%20-%20x_2%29%20%5Ccdots%20%28x%20-%20x_n%29)
In which a is the leading coefficient.
If a complex number is a root of a function, it's conjugate will also be a root. Thus, with three pairs of complex-conjugate roots, for example,
, a sixth degree function with no real zeros is formed, so the answer is Yes.
More can be learned about the Factor Theorem at brainly.com/question/24380382