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miv72 [106K]
3 years ago
11

How do you solve exponents?

Mathematics
1 answer:
Wittaler [7]3 years ago
6 0
<span>Learn the correct words and vocab for exponent problems. ...Multiply the base repeatedly for the number of factors represented by the exponent. ...Solve an expression: Multiply the first two numbers to get the product. ...<span>Multiply that answer to your first pair (16 here) by the next number.

</span></span>
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The distance from Earth to the moon is approximately 2.48 × 105 miles. What is this distance in standard form?
Natasha2012 [34]
C.248,000 
to find standard form if the power is positive move the decimal that many places to the right. If the power is negative move the decimal that many times to the left. 
8 0
3 years ago
please help, this is an algebra 2 question :) I attached the problem in a photo - simplify the following expression
MrRa [10]

Answer:

\frac{x^2+19x-56}{4x^2-32x}

Step-by-step explanation:

To add two fractions we need a common denominator. Just by looking at the two, there are no common factors. This means the denominator would be the product of the two: 4x(x-8). In order to obtain this, we multiply the first fraction by (x-8)/(x-8) - 1, and the second by 4x/4x - 1:

\frac{x+7}{4x} *\frac{x-8}{x-8} +\frac{5}{x-8}*\frac{4x}{4x}

We can use the distributive property to simplify:

\frac{x^2-x-56}{4x(x-8)} +\frac{20x}{4x(x-8)}

The sum of the two is:

\frac{x^2+19x-56}{4x^2-32x}

7 0
3 years ago
Help Pleasee i need help really bad
Sergeu [11.5K]
(0,-3) (2,1) is the two points we are going to use.

M=(1--3)/(2-0)=4/2=2

The slope is 2
6 0
3 years ago
Read 2 more answers
What is the slope of the line?
Alekssandra [29.7K]

Answer:

I will be needing a picture for this question. However, here is a formula to help you out! y2-y1/x2-x1    (the Xs are on the bottom, and the Ys are on the top. Pick an 2 ordered pairs, and then put them like the formula. X2  and Y2 are an ordered pair, same for X1 and Y1.) Hope this helped ;)

Step-by-step explanation:

5 0
3 years ago
69 points!!!
Amiraneli [1.4K]

Answer:

C)  The solution for the given system of equations are A(0,-5) and B(-4,3)

Step-by-step explanation:

The given system of equation are : x^{2}  + y^{2}  = 25\\2x  + y  = -5

from equation 2, we get   y = -5 - 2x .

Put the above value of y in the equation (1).

We get: x^{2}  + y^{2}  = 25  \implies x^{2}  + (-5-2x)^{2}  = 25

By ALGEBRAIC IDENTITY:

(a+b)^{2}   = a^{2}  +  b^{2}  + 2ab\\ (-5-2x)^{2} = (-5)^{2}  +  (-2x)^{2}  + 2(-5)(-2x)

or, x^{2}  + (-5-2x)^{2}  = 25  \implies x^{2} + (25  +  4x^{2}  + 20x)  = 25

or, 5x^{2}  + 20x = 0  \implies x(5x + 20) = 0

⇒ x = 0 or,   x  = -20/5 = -4

So, the possible values for x are: x  = 0 or  x  = -4

If x  = 0, y = -5-2x = -5-2(0) = -5

and if x = -4, y = -5 -2(-4)   = -5 + 8  = 3

Hence, the solution for the given system of equations are A(0,-5) and B(-4,3)

8 0
3 years ago
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