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miv72 [106K]
3 years ago
11

How do you solve exponents?

Mathematics
1 answer:
Wittaler [7]3 years ago
6 0
<span>Learn the correct words and vocab for exponent problems. ...Multiply the base repeatedly for the number of factors represented by the exponent. ...Solve an expression: Multiply the first two numbers to get the product. ...<span>Multiply that answer to your first pair (16 here) by the next number.

</span></span>
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A new employee charged $3980 on his credit card to relocate for his first job.After noticing that the interest rate for his bala
olga nikolaevna [1]

Answer:

that should be how you would solve those questions..

8 0
3 years ago
Free points to y'all. 1+1+1*0​
DiKsa [7]
I think it’s probably 12
7 0
3 years ago
Read 2 more answers
The formula F=9/5(K−273.15)+32
Lyrx [107]
Just subtract 32, then divide by 9/5 (or multiply by the reciprical) then add 273.15.
K=5/9(F-32)+273.15
3 0
4 years ago
What is the difference between the mean of each set?<br><br>a) 4<br>b) 5<br>c) 7<br>d) 9<br>​
Xelga [282]
Mean is the average

So the first mean is 11
The second one is 14.7 so round to 15

15-11 is 4. Hope that is correct
7 0
3 years ago
Read 2 more answers
Locate the point on the line segment between A(3, -5) and B(13, -15) given that the point is 4/5 of the way from A to B. Show yo
SVETLANKA909090 [29]

Answer:

C ( 11 , -11 )

Step-by-step explanation:

Solution:-

We are given two points in the cartesian coordinate system as:

                   A ( 3 , -5 )              B ( 13 , -15 )

The point C lies on the line segment from A to B. The ratio of segment given is:

                              AC / AB = 4 / 5

To solve such type of problems. We will use vector equation of line AC.

To form a vector equation of line representing AB. We will first determine the direction vector ( d ) that is parallel to the line AB as follows:

                 d = OB - OA

                 d = < 13 , -15 > - < 3 , -5 >  

                 d = < 10 , -10 >

The fixed point on the line is taken. We will take point A. The vector equation of line from point A to point B is expressed as:

                < x , y > = OA + s*d

                < x , y > = < 3, -5 > + s* < 10 , -10 >  

The above equation satisfies all the points that lies on the line AB. To determine the coordinates of ( C ). We will plug in the appropriate value of parameter ( s ) and evaluate.

So point C is 4/5 th the magnitude of the distance AB from A. Hence, s = 4/5 as follows:

               < x , y > = < 3 , -5 > + ( 4/5 ) * < 10 , -10 >  

               < x , y > = < 3 , -5 > + < 8 , -8 >  

              < x , y > = < 11 , -11 >   ... Answer

8 0
3 years ago
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