Choose the correct zeros for the following quadratic function.

Mathematics

2 answers:

irinina [24]3 years ago

7 0

Answer:

Step-by-step explanation:

C.;)

bezimeni [28]3 years ago

3 0

Replace f(x) with 0. Then solve for x

f(x) = x^2 + 5x - 14
0 = x^2 + 5x - 14
x^2 + 5x - 14 = 0
(x+7)(x-2) = 0 ... factor (think of two numbers that multiply to -14 and add to 5)
x+7 = 0 or x-2 = 0
x = -7 or x = 2

The two zeros, roots, or x intercepts are x = -7 or x = 2

Answer: Choice C) {2, -7}

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Question 14 of 25What is the complete factorization of the polynomial below?x³+x² + 4x+4O A. (x-1)(x+2)(x+2)B. (x + 1)(x + 2)(x

mote1985 [20]

GIVEN:

We are given the following polynomial;

$x^3+x^2+4x+4$

Required;

We are required to factorize this polynomial completely.

Step-by-step explanation;

To factorize this polynomial, we start by grouping;

$(x^3+x^2)+(4x+4)$

We now take the common factor in each group;

$\begin{gathered} x^2(x+1)+4(x+1) \\ \\ (x^2+4)(x+1) \end{gathered}$

Next, we factorize the first parenthesis. To do this we set the equation equal to zero and solve for x as follows;

$\begin{gathered} x^2+4=0 \\ \\ Subtract\text{ }4\text{ }from\text{ }both\text{ }sides: \\ \\ x^2=-4 \\ \\ Take\text{ }the\text{ }square\text{ }root\text{ }of\text{ }both\text{ }sides: \\ \\ x=\pm\sqrt{-4} \\ \\ x=(\pm\sqrt{-1}\times\sqrt{4}) \\ \\ x=\pm2i \end{gathered}$

Therefore, the factors of the other parenthesis are;