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ikadub [295]
3 years ago
5

The temperature in Grand Rapids, Michigan on January 8 was 30 degrees Fahrenheit. The temperature two days later was -8 degrees

Fahrenheit. What was the difference in temperature between the two days?
-38 degrees Fahrenheit
-22 degrees Fahrenheit
22 degrees Fahrenheit
38 degrees Fahrenheit
Mathematics
2 answers:
mylen [45]3 years ago
5 0
It’s -38 degrees Fahrenheit
EleoNora [17]3 years ago
4 0
The answer is -38 fahrenheit.
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Step-by-step explanation:

Step 1: Add 5 to both sides.

−3x−5+5=16+5

−3x=21

Step 2: Divide both sides by -3.

−3x/−3=21/−3

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The length of the longer leg of a right triangle is 4 inches more than twice the length of the shorter leg. the length of the hy
Serjik [45]

The Pythagorean's Theorem for our situation would look like this:

shortleg^2+longleg^2=hypotenuse^2

So let's call the short leg s, the long leg l and the hypotenuse h. It appears that all our measurements are based on the measurement of the short leg. The long leg is 4 more than twice the short leg, so that expression is l=2s+4; the hypotenuse measure is 6 more than twice the short leg, so that expression is h=2s+6. And the short leg is just s. Now we can rewrite our formula accordingly:

s^2+(2s+4)^2=(2s+6)^2

And of course we have to expand. Doing that will leave us with

s^2+4s^2+8s+8s+16=4s^2+12s+12s+36

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s^2-8s-20=0

That is now a second degree polynomial, a quadratic to be exact, and it can be factored several different ways. The easiest is to figure what 2 numbers add to be -8 and multiply to be -20. Those numbers would be 10 and -2. Since we are figuring out the length of the sides, AND we know that the two things in math that will never EVER be negative are time and distance/length, -2 is not an option. That means that the short side, s, measures 10. The longer side, 2s+4, measures 2(10)+4 which is 24, and the hypotenuse, 2s+6, measures 2(10)+6 which is 26. So there you go!

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3 years ago
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Mrac [35]

Answer:

£1 = 25 hits

Step-by-step explanation:

Will get the equation is

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x = What we want to find

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The size of the left upper chamber of the heart is one measure of cardiovascular health. When the upper left chamber is enlarged
Temka [501]

Answer:

a) 0.283  or 28.3%

b) 0.130 or 13%

c) 0.4 or 40%

d) 30.6 mm

Step-by-step explanation:

z-score of a single left atrial diameter value of healthy children can be calculated as:

z=\frac{X-M}{s} where

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Then

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And P(z<−0.574)=0.283

b) proportion of healthy children who have left atrial diameters greater than 32 mm

= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm

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P(z<0.702)=0.7587

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Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4

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P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.

Then P(z<z*)=0.8 and z*=0.84. That is

0.84=\frac{X-26.7}{4.7}  solving this equation for X we get X=30.648

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