Answer:
4 is the answer
Step-by-step explanation:
they lost 4matches
Answer: The equation has a positive y-intercept
This is because the constant is +10
<span>Angle TSQ measures 68 degrees.
When a ray bisects an angle, it divides it into two equal parts. Each part is one-half the measurement of the original angle. Several rays are described as bisecting different angles. I would sketch a diagram to keep track of all the different rays and angles.
A. Since angle RST is bisected by ray SQ, angle RSQ and angle QST are each half the size of angle RST.
B. Since angle RSQ is bisected by ray SP, angle RSP and angle PSQ are each half the size of angle RSQ.
C. Since angle RSP is bisected by ray SV, angle RSV and angle VSP are each half the size of angle RSP.
We are given the measurement of angle VSP as 17 degrees. To find the measure of angle RSP, we notice in statement C above that VSP is half the size of angle RSP. If we double angle VSP's measurement (multiply by 2), we get angle RSP measures 34 degrees.
Using similar logic and statement B above, we double RSP's measurement of 34 to get angle RSQ's measurement. Double 34 is 68, angle RSQ's measurement in degrees.
From statement A above, we notice that RSQ's measurement is equal to that of angle QST's. Therefore, angle QST also measures 68 degrees. However, the question asks us to find the measurement of angle TSQ. However, angle QST and angle TSQ are the same. Either description can be used. Therefore, the measurement of angle TSQ is 68 degrees.</span>
Answer:
67
Step-by-step explanation:
You have to use fractions to show your work and I'm not going to do that but just know that it is the answer.
Answer:
Step-by-step explanation:
Given that the figure is made up of portion of a square and a semicircle, we have;
BC ≅ AB = 6 cm
The area of semicircle BC with radius BC/2 = 3 is 1/2×π×r² = 1/2×π×3² = 4.5·π cm²
Triangle ABC = 1/2 × Area of square from which ABC is cut
The area of triangle ABC = 1/2×Base ×Height = 1/2×AB×BC = 1/2×6×6 = 18 cm²
The area of the figure = The area of semicircle BC + The area of triangle ABC
The area of the figure = 4.5·π cm² + 18 cm² = 
.
