Answer:the horizontal displacement is 34.64 meters
The maximum height is 15 meters
Step-by-step explanation:
As the ball moves from the ground at 30 degrees, it travels through a parabolic path. It can therefore be likened to a projectile. The horizontal displacement to where it lands is the range. The formula for determining range,R is
R = U^2Sin2#)/g
Where
U represents the initial velocity of the ball
g is acceleration due to gravity
# represents the angle above the horizontal.
From the information given
# = 30 degrees
U = 20 m/s
g = 10m/s^2
R = 20^2Sin2×30)/10 = (400Sin60)/20 = (400×0.8660)/10
= 34.64 meters
To determine the maximum height of the ball, H,
H = (U^2Sin^2#)/2g
H = (20^2 × Sin^2 30)/2×10
H = (400 × 0.866^2)/20 = 15 meters
Answer:
the area of the triangle is 20 units, and the answer to the expression is also 20, so its equal to each other. 20=20
the area of the trapezoid is 38.5 units
Step-by-step explanation:
Answer:
dy/dx = -5y - y/x
Step-by-step explanation:
In xy + 5x = 30
Differentiating xy implicitly
y + xdy/dx
Assuming u = xy
In xy = In u
Differentiating In u = 1/u = 1/xy
Differentiating 5x = 5 and differentiating a constant (30) = 0
1/xy(y + xdy/dx) + 5 = 0
(y + xdy/dx)/xy = -5
(y + xdy/dx) = -5xy
xdy/dx = -5xy - y
dy/dx = = (-5xy - y)/x
dy/dx = -5y - y/x
Answer:
2.
Step-by-step explanation:
4 because you would say "forty three thousand..." three would be the one thousands place, and 4 would be the ten thousands place.
