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Lena [83]
3 years ago
13

How do I solve 4/9+9/2 and write my answer as a mixed number?

Mathematics
1 answer:
jenyasd209 [6]3 years ago
8 0

9 has factors of 3*3.

2 is prime, so no factors.

from those two denominators, we can get the LCD of hmmm simply their product, namely 18.

\bf \cfrac{4}{9}+\cfrac{9}{2}\implies \stackrel{\textit{using the LCD of 18}}{\cfrac{(2)4+(9)9}{18}}\implies \cfrac{8+81}{18}\implies \cfrac{89}{18}\implies 4\frac{17}{18}

now, recall that, to get the mixed fraction, we divide 89 ÷ 18, the quotient goes up front, the "4", and the remainder is the one atop, the "17".

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An example problem in a Statistics textbook asked to find the probability of dying when making a skydiving jump.
MArishka [77]

Answer:

(a) 0.999664

(b) 15052

Step-by-step explanation:

From the given data of recent years,  there were about 3,000,000 skydiving jumps and 21 of them resulted in deaths.

So, the probability of death is \frac{21}{3000000}==0.000007.

Assuming, this probability holds true for each skydiving and does not change in the present time.

So, as every skydiving is an independent event having a fixed probability of dying and there are only two possibilities, the diver will either die or survive, so, all skydiving can be regarded as is Bernoulli's trial.

Denoting the probability of dying in a single jump by q.

q=7\times 10^{-6}=0.000007.

So, the probability of survive, p=1-q

\Rightarrow p=1-7\times 10^{-6}=0.999993.

(a) The total number of jump he made, n=48

Using Bernoulli's equation, the probability of surviving in exactly 48 jumps (r=48) out of 48 jumps (n=48) is

=\binom(n,r)p^rq^{n-r}

=\binom(48,48)(0.999993)^{48}(0.000007)^{48-48}

=(0.999993)^{48}=0.999664 (approx)

So, the probability of survive in 48 skydiving is 0.999664,

(b) The given probability of surviving =90%=0.9

Let, total n skydiving jumps required to meet the surviving probability of 0.9.

So, By using Bernoulli's equation,

0.9=\binom {n }{r} p^rq^{n-r}

Here, r=n.

\Rightarrow 0.9=\binom{n}{n}p^nq^{n-n}

\Rightarrow 0.9=p^n

\Rightarrow 0.9=(0.999993)^n

\Rightarrow \ln(0.9)=n\ln(0.999993) [ taking \log_e both sides]

\Rightarrow n=\frac {\ln(0.9)}{\ln(0.999993)}

\Rightarrow n=15051.45

The number of diving cant be a fractional value, so bound it to the upper integral value.

Hence, the total number of skydiving required to meet the 90% probability of surviving is 15052.

3 0
3 years ago
Help me answer please
fiasKO [112]

Answer:

25

Step-by-step explanation:

b=4x+1    h=x+1     A=175

A=bh

Substitute: 175=(4x+1)(x+1)

Expand: 175=4x^2+5x+1

Subtract 175

4x^2+5x-174=0

Solve w/quadratic formula

(-5 <u>+</u> sqrt(25+2784))/8

Simplify: x=6 or -29/4

Distance is positive, so x=6

4x+1=4*6+1=25


6 0
3 years ago
At a party of 102 people,17 lb of potato salad is served. a. Write and solve an equation to find how many people each pound of p
Novay_Z [31]

Each pound of potato salad serves 6 people and the average number of pounds of potato salad that each person is served will be \frac{1}{6} pound.

<u><em>Explanation</em></u>

At a party of 102 people, 17 pounds of potato salad is served.

<u>a.</u>  Suppose, each pound of potato salad is served to x number of people.

So, 17 pounds of salad is served to (17*x) or 17x number of people. That means......

17x= 102\\ \\ x= \frac{102}{17}=6

So, each pound of potato salad is served to 6 people.


<u>b.</u>  Suppose, the average number of pounds of potato salad that each person is served is  y

So, the total number of pounds of salad, served to 102 people = (y*102) pounds =102y pounds. That means .....

102y= 17\\ \\ y= \frac{17}{102}= \frac{1}{6}

So, the average number of pounds of potato salad that each person is served will be  \frac{1}{6} pound.

3 0
3 years ago
before the use of calculators, mathematicians developed and used detailed tables of values of the sine, cosine and tangent ratio
Debora [2.8K]

Answer:

the answer is  bc of my knowledge XD XD XD hahaha

Step-by-step explanation:

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3 0
3 years ago
Can i have help soon please?
zavuch27 [327]
M<1 = 1/2(b-d)

answer is C. third choice
3 0
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