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2 years ago

What's the difference in size between 1 1/2 and 1/4?

2 answers:

7 0

Well if you convert 1 1/2 to have common factors you would get 1 2/4 so the size difference would be 1 1/4 (you just subtract the two numbers)

Yuliya22 [10]2 years ago

3 0

1 1/4 is the answer

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Please answer both with work,please use a paper and picture, thanks

Irina-Kira [14]

Answer:

a. $\frac{\textbf{17}}{\textbf{4}}$

b. $\frac{\textbf{3}}{\textbf{8}}$

Step-by-step explanation:

a. $\textbf{3} \hspace{1mm} \textbf{+} \hspace{1mm} \textbf{1}\frac{\textbf{1}}{\textbf{4}}$

A mixed fraction of the form $a\frac{x}{y} = a + \frac{x}{y}$

$\therefore 3 + 1\frac{1}{4} = 3 + 1 + \frac{1}{4}$

$= 4 + \frac{1}{4}$

$= \frac{\textbf{17}}{\textbf{4}}$

b. $\textbf{2} \hspace{1mm} \textbf{-} \hspace{1mm} \textbf{1}\frac{\textbf{5}}{\textbf{8}}$

A mixed fraction of the form $-c\frac{a}{b} = - c - \frac{a}{b}$

$\therefore 2 - 1\frac{5}{8} = 2 - 1 - \frac{5}{8}$

$= 1 - \frac{5}{8}$

$= \frac{8 - 5}{8}$

$= \frac{\textbf{3}}{\textbf{8}}$

Hence, the answer.

8 0

3 years ago

- Ms. Ali needs to have her car repaired but does not want to spend more than $225

Alika [10]

Answer:

Step-by-step explanation:

4 0

2 years ago

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A dog breeder would like to know how many Dalmatian puppies are typically born in a litter. He conducts some research and select

podryga [215]

Answer:

c. 6.2 ± 2.626(0.21)

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 101 - 1 = 100

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.995$ . So we have T = 2.626

The confidence interval is:

$\overline{x} \pm M$

In which $\overline{x}$ is the sample mean while M is the margin of error.

The distribution of the number of puppies born per litter was skewed left with a mean of 6.2 puppies born per litter.

This means that $\overline{x} = 6.2$

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.626\frac{2.1}{\sqrt{101}} = 2.626(0.21)$

In which s is the standard deviation of the sample and n is the size of the sample.

Thus, the confidence interval is:

$\overline{x} \pm M = 6.2 \pm 2.626(0.21)$

And the correct answer is given by option c.

5 0

3 years ago

Find the area of this figure. Please show work if you can!

Yuri [45]

Here is the answer if you can't read my writing than just ask. also if you have any questions about how I got something feel free to ask

8 0

2 years ago

Which one is the better deal, the 8 inch little zip for $6.25 or the 11 inch big zip for $7.75.

natta225 [31]

Answer:

the 11 inch big zip for 7.75

Step-by-step explanation:

6 0

2 years ago

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