All categories

3 years ago

Can someone help me with # 2??

Mathematics

1 answer:

creativ13 [48]3 years ago

6 0

Answer:

;lkasjdf;lkjasdf;lkjasdflkjasdflkjasdl;fkjasdflkjasd;lkfjasld;kjflaskdjf;laskjf;lkasdjf;lkasdjf;lkasdjf;lksadjf;lkasdjfl;kasdjf;lkasdjf;laskdjf;lkasdjfl;aksdjflkasdjf;lksadjf;lksajf;lkjasdkfljasdk;lfjkasdjfjasdkfjkasdjkfj;lkasdjkf

Step-by-step explanation:

You might be interested in

There are 4 grams of fiber in 1/2 cup of oats how many grams of fiber are in 3 1/2

Anna71 [15]

Answer:

28 grams

Step-by-step explanation:

In cup of oats, amount of fiber is = 4 grams

In 1 cup of oats amount of fiber is = = 8 grams

So, in or cups of oats, amount of fiber is = 28 grams

3 0

3 years ago

Read 2 more answers

Put these questions in order from least to greatest 3/8 19/24 2/3

aleksandr82 [10.1K]

First 3/8, second 2/3, and third 19/24

4 0

3 years ago

A student carried out an experiment to determine the amount of vitamin C in a tablet sample. He performed 5 trials to produce th

ivolga24 [154]

Answer:

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

P-value = 0.166.

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(490+502+505+495+492)\\\\\\M=\dfrac{2484}{5}\\\\\\M=496.8\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}((490-496.8)^2+(502-496.8)^2+(505-496.8)^2+(495-496.8)^2+(492-496.8)^2)}\\\\\\s=\sqrt{\dfrac{166.8}{4}}\\\\\\s=\sqrt{41.7}=6.5\\\\\\$

Then, we can perform the hypothesis t-test for the mean.

The claim is that the amount of vitamin C in a tablet sample is different from 500 mg.

Then, the null and alternative hypothesis are:

$H_0: \mu=500\\\\H_a:\mu< 500$

The significance level is 0.05.

The sample has a size n=5.

The sample mean is M=496.8.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.5.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6.5}{\sqrt{5}}=2.907$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{496.8-500}{2.907}=\dfrac{-3.2}{2.907}=-1.1$

The degrees of freedom for this sample size are:

$df=n-1=5-1=4$

This test is a left-tailed test, with 4 degrees of freedom and t=-1.1, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=P(t$

As the P-value (0.166) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

4 0

3 years ago

Explain and demonstrate how to turn 4/20 into a percent

iren2701 [21]

Answer:

20%

Step-by-step explanation:

We can start by looking at it as a ratio, so 4 divided by 20 and 4/20 = 0.2, so that would be 20% viewing 1=100%.

Another way is

20 here is 100%, and for 20 to equal 100, we have to multiply it by 5. To balance it out, multiply the top by 5 as well, and 4 * 5 =20. Therefore, 4/20 = 20%

4 0

3 years ago

Which formula should be used to calculate the amount of paper needed?

bogdanovich [222]

Answer:

Step-by-step explanation:

I=PRT where I =interest P=principal, R=rate, and T =time is

3 0

3 years ago