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blagie [28]
3 years ago
5

Jeremiah lives in New York City and takes a taxi almost everywhere he goes. In order to calculate the price of his taxi ride,

Mathematics
1 answer:
ohaa [14]3 years ago
4 0

Answer: 2.50 is the fee he must pay before the taxi takes him anywhere

Step-by-step explanation: since it is an add on, and it is not multiplied by the variable, we know this is a one time expense, meaning it is the base charge.

The answer is A

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Lapatulllka [165]

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5

Step-by-step explanation:

26/5= 5.2

the greatest whole number that can be chosen is 5.

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Kazeer [188]

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Step-by-step explanation:

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4 years ago
1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING
iogann1982 [59]

If

y=\displaystyle\sum_{n=0}^\infty a_nx^n

then

y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

The ODE in terms of these series is

\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0

\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}

We can solve the recurrence exactly by substitution:

a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0

\implies a_n=\dfrac{(-2)^n}{n!}a_0

So the ODE has solution

y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}

which you may recognize as the power series of the exponential function. Then

\boxed{y(x)=a_0e^{-2x}}

7 0
3 years ago
(5x3)+8 divides by 4 to the power of 2 +8
REY [17]
The answer is 23.5 ...probably
6 0
4 years ago
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