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3 years ago

11

I need help please??!!

1 answer:

atroni [7]3 years ago

5 0

Answer:

(2,-2)

Step-by-step explanation:

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You have 25 coins that total $1.45. The only coins you have are quarters and pennies. How many of each coin do you have?

Snowcat [4.5K]

Answer:You have 4 quarters and 45 pennines

Step-by-step explanation:

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2 years ago

Tom had 7/12 of a pizza. His little sister came along and took 2/5 of his pizza away. How much pizza does Tom have left?

ASHA 777 [7]

I believe the answer is 11/60 of a pizza. To get this, you must find common denominators of the two fractions. That would be 60 (12x5). You must multiply in a form of one (2x12=24, 7x5=35). Therefore, 35/60-24/60=11/60

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3 years ago

If f(x) = 5x + 40, what is f(x) when x = -5?

Maru [420]

Hello!

Answer:

$\huge\boxed{f(-5) = 15}$

f(x) = 5x + 40

x = -5

Substitute the value of "x" into the equation:

f(-5) = 5(-5) + 40

Simplify:

f(-5) = -25 + 40

f(-5) = 15.

6 0

3 years ago

Read 2 more answers

A. Given f(x)=x3 use the Mean Value Theorem and find all point c, 0

m_a_m_a [10]

Answer:

a) $x \approx 1.155$ , b) $x = \pm\frac{i}{2}$ , for all $i = \{0,1,2,3,... \}$

Step-by-step explanation:

a) The slope associated with the mean value is:

$f'(c) =\frac{f(2)-f(0)}{2 - 0}$

$f'(c) = \frac{8-0}{2-0}$

$f'(c) = 4$

Let differentiate the function:

$f'(x) = 3\cdot x^{2}$

The value associated with the slope is:

$3\cdot x^{2} = 4$

$x = \sqrt{\frac{4}{3} }$

$x \approx 1.155$

b) The slope associated with the mean value is:

$f'(c) =\frac{f(2)-f(0)}{2 - 0}$

$f'(c) = \frac{1-1}{2-0}$

$f'(c) = 0$

Let differentiate the function:

$f'(x) = - 2\pi \cdot \sin (2\pi\cdot x)$

The value associated with the slope is:

$-2\pi\cdot \sin (2\pi\cdot x) = 0$

$\sin (2\pi\cdot x) = 0$

$2\pi\cdot x = \sin^{-1} 0$

$2\pi \cdot x = \pm \pi \cdot i$ , for all $i = \{0,1,2,3,... \}$

$x = \pm\frac{i}{2}$ , for all $i = \{0,1,2,3,... \}$

3 0

3 years ago

What percentage is £95 of £250?

bagirrra123 [75]

$\frac{95}{250}\cdot100\%=\frac{95}{5}\cdot2\%=19\cdot2\%=38\%\\\\other\ method:\\\\ \begin{array}{ccc}250&-&100\%\\\\95&-&p\%\end{array}\ \ \ \ |cross\ multiply\\\\250p=95\cdot100\ \ \ \ |divide\ both\ sides\ by\ 250\\\\p=\frac{9500}{250}\\\\p=38\ (\%)\\\\Answer:\£95\ is\ 38\%\ of\ \£250.$

7 0

2 years ago