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Alborosie
3 years ago
8

Whats the cubed root 64/343

Mathematics
2 answers:
Leno4ka [110]3 years ago
7 0
Cubing them each it would be
4/7
Lisa [10]3 years ago
4 0
The answer is 4/7, or 0.571428...

Hope this helped! ☺♥
You might be interested in
If the side of every square is 2 centimeters, how many centimeters is the circumfence of the figure?
Mandarinka [93]

Answer:

<h2>          76 cm</h2>

Step-by-step explanation:

|FE| = |CB| = 4\cdot2=8\,cm\\\\|ED|=|DC|= \sqrt{(3\cdot2)^2+(4\cdot2)^2}= \sqrt{6^2+8^2}=\sqrt{100}=10\,cm\\\\|FA|=|AB|= \sqrt{(6\cdot2)^2+(8\cdot2)^2}= \sqrt{144+256}=\sqrt{400}=20\,cm\\\\\\Circumference = FE+ED+DC+CA+AB+FA\\\\Circumference =8+10+10+8+20+20=76\,cm

3 0
3 years ago
PLS HELP I NEED TO FIND THE ACTUAL DISTANCE BETWEEN WACH OAIR IF CITIES AND IF NECESSARY I HAVE TO ROUND TO THE NEAREST TENTH
kolbaska11 [484]

1; 127 mi

2;78

Sorry i did not know the other answers

I hoped this helped

8 0
3 years ago
What is the midpoint of GH if the coordinates of G and H are (2,5) and (-6,3)
spayn [35]
Mid point of x:
{2-(-6)} : 2
8 : 2
4

mid point of y:
(5-3) : 2
2 : 2
1

so (4,1)
7 0
3 years ago
All questions to be solved using linear combination.
monitta
1)
I:x-y=-7
II:x+y=7

add both equations together to eliminate y:
x-y+(x+y)=-7+7
2x=0
x=0

insert x=0 into II:
0+y=7
y=7

the solution is (0,7)

2)
I: 3x+y=4
II: 2x+y=5

add I+(-1*II) together to eliminate y:
3x+y+(-2x-y)=4+(-5)
x=-1

insert x=-1 into I:
3*-1+y=4
y=7

the solution is (-1,7)

3)

I: 2e-3f=-9
II: e+3f=18

add both equations together to eliminate f:
2e-3f+(e+3f)=-9+18
3e=9
e=3

insert e=3 into I:
2*3-3f=-9
-3f=-9-6
-3f=-15
3f=15
f=5

the solution is (3,5)

4)
I: 3d-e=7
II: d+e=5

add both equations together to eliminate e:
3d-e+(d+e)=7+5
4d=12
d=3

insert d=3 into II:
3+e=5
e=2

the solution is (3,2)

5)
I: 8x+y=14
II: 3x+y=4

add I+(-1*II) together to eliminate y
8x+y+(-3x-y)=14-4
5x=10
x=2

insert x=2 into II:
3*2+y=4
y=4-6
y=-2

the solution is (2,-2)
8 0
3 years ago
A bouncing ball reaches a height of 54 inches at its first peak, 36 inches at its second peak, and 24 inches at its third peak.
steposvetlana [31]
54, 36, 24 are the 1st 3 element of a geometric progression with 2/3 as a common ratio: PROOF:
the 1st term is 54, (a₁= 54) the 2nd term a₂ = 24, then
(a₂ = a₁.r) or 36 = 54.r → r= 36/54 = 2/3. Same logique for the 3rd term. 
So 2/3 is common ratio. We know that :U(n) = a.(r)ⁿ⁻¹. Then if a =54 and r = x (given by the problem), then f(x) = 54.xⁿ⁻¹
n, being the rank of any element of this geometric progression

7 0
3 years ago
Read 2 more answers
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