3 years ago

Drag each rational number to the correct location on the table.

Mathematics

1 answer:

andrey2020 [161]3 years ago

3 0

Answer:

Step-by-step explanation:

Positive: -1/-3, -2/-2, +2/+3, -1/+3

the rest of them are negative

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The solution to (d+4)^2=9 is D=

Allushta [10]

Answer:

$\boxed{\sf d = -1 \ \ \ or \ \ \ d = -7}$

Step-by-step explanation:

$\sf Solve \: for \: d \: over \: the \: real \: numbers: \\ \sf \implies {(d + 4)}^{2} = 9 \\ \\ \sf Take \: the \: square \: root \: of \: both \: sides: \\ \sf \implies \sqrt{ {(d + 4)}^{2} } = \sqrt{9} \\ \\ \sf 9 = {3}^{2} : \\ \sf \implies \sqrt{ {(d + 4)}^{2} } = \sqrt{ {(3)}^{2} } \\ \\ \sf \implies d + 4 = \pm 3 \\ \\ \sf \implies d + 4 = 3 \: \: \: \: \: or \: \: \: \: \: d + 4 = - 3 \\ \\ \sf Subtract \: 4 \: from \: both \: sides: \\ \sf \implies d + (4 - 4)= 3 - 4 \: \: \: \: \: or \: \: \: \: \: d + (4 - 4) = - 3 - 4 \\ \\ \sf \implies d = - 1 \: \: \: \: \: or \: \: \: \: \: d = - 7$