All categories

3 years ago

What's the answer?????????????

Mathematics

1 answer:

Taya2010 [7]3 years ago

3 0

Answer:

BD = 12 :)

Step-by-step explanation:

Alright, we'll need the Pythagorean theorem for this!

So, the length of AC is 10. That means the lengths of AD and DC are both half of that, which is 5 :)

DC = 5

We already know that BC = 13, so we can plug in these values into the pythagorean theorem for the right triangle BDC:

BD^2 + DC^2 = BC^2

BD^2 + 5^2 = 13^2

BD^2 + 25 = 169

BD^2 = 169 - 25 = 144

BD = √144 = 12 :)

You might be interested in

Formulate the situation as a linear programming problem by identifying the variables, the objective function, and the constraint

abruzzese [7]

Answer:

zero goats and 120 Ilamas to get profit of $15,120

Step-by-step explanation:

Goats: G

Ilamas: l

Explicit constraints:

2G + 5l ≤ 400

100G+ 80l≤ 13,200

Implicit constraints

G≥0

I≥0

P= 84G+ 126l

See attachment for optimal area

substituting coordinats of optimal region in profit equation to get profit

When G= 132, l=0

P=84(132) + 126(0)

P=11,088

When G=0, l=120

P=84(0)+ 126(120)

P = 15120

When G= 100, l=40

P=84(100)+126(40)

P=13440

3 0

3 years ago

What is 12a =? Talking about Math :/

frosja888 [35]

Answer: 12a=48

Step-by-step explanation:

4a+6b=10

4a=10-6b

a=(10-6b)/4

a=(5-3b)/2

2a-4b=12

2((5-3b)/2)-4b=12

(5-3b)-4b=12

5-7b=12

-7b=7

b=-1

2a-4b=12

2a-4(-1)=12

2a+4=12

2a=8

a=4

a=4, b=-1

12a=48

4 0

3 years ago

- 30 = 12 – 6r<br><br> Pls help

oee [108]

Answer: r = 7

Step-by-step explanation:

Subtract 12 from both sides to isolate the r variable. You have -42 = -6r. Divide both sides by -6 to get r by itself and you get r = 7. Verify by substituting 7 as the r value and solving the equation.

8 0

3 years ago

Read 2 more answers

Assume that there is a 4% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit

kap26 [50]

Answer:

a) 99.84% probability that during a year, you can avoid catastrophe with at least one working drive

b) 99.999744% probability that during a year, you can avoid catastrophe with at least one working drive

Step-by-step explanation:

For each disk drive, there are only two possible outcomes. Either it works, or it does not. The disks are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

4% rate of disk drive failure in a year.

This means that 96% work correctly, $p = 0.96$

a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk drive, what is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is $P(X \ geq 1)$ when $n = 2$

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.96)^{0}.(0.04)^{2} = 0.0016$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0016 = 0.9984$

99.84% probability that during a year, you can avoid catastrophe with at least one working drive

b. If copies of all your computer data are stored on four independent hard disk drives, what is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is $P(X \ geq 1)$ when $n = 4$

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.96)^{0}.(0.04)^{4} = 0.00000256$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.00000256 = 0.99999744$

99.999744% probability that during a year, you can avoid catastrophe with at least one working drive

7 0

3 years ago

I need it by morning and I need the work HELP!!!

valentina_108 [34]

1. 5/6 = 10/12

3/4 = 6/8

2. 2/9 = 4/18

4/12 = 1/3

3. 6/7 = 12/14

1/2 = 2/4

4. 5/9 = 10/18

3/18 = 1/6

5. 1/6 = 2/12

1/9 = 2/18

6. 3/8 = 6/12

5/6 = 10/12

8 0

3 years ago