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3 years ago

How do you solve this equation -8x=3

Mathematics

2 answers:

alina1380 [7]3 years ago

8 0

Answer:

x= 3/-8 it's a fraction bc 8 can't go into 3

spayn [35]3 years ago

7 0

-8x = 3
Divide 3 by -8 to get x alone
x = 3/-8

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(06.01)

MAVERICK [17]

After solving I have come up with 6 2/9 or 6.22222.

4 0

3 years ago

Assume the world catch of fish in 1950 was 12 million tons and in 1955 it was 96 million tons.

Rama09 [41]

The rate of change is 16.8 million tons per year

Solution:

Given that, the world catch of fish in 1950 was 12 million tons and in 1955 it was 96 million tons

The average rate of change is given by formula:

$\text{ Average rate of change } = \frac{\text{ change in value }}{\text{ number of years }}$

Value in 1950 = 12 million tons

Value in 1955 = 96 million tons

Change in value = value in 1955 - value in 1950

Change in value = 96 million - 12 million = 84 million tons

Number of years = 1950 to 1955 = 5 years

Substitute the given values in formula,

$\text{ Average rate of change } = \frac{84 \text{ million tons}}{5} = 16.8 \text{ million tons}$

Thus rate of change is 16.8 million tons per year

5 0

3 years ago

Which best explains why this triangle is or is not a right triangle?

erastovalidia [21]

Answer:

<h2>This triangle is a right triangle:</h2><h2>36² + 15² = 39².</h2>

Step-by-step explanation:

If a ≤ b <c is the length of the sides of a right triangle, then:

$a^2+b^2=c^2$

We have

$a=15\ in,\ b=36\ in,\ c=39\ in$

Check the equality:

$L_s=15^2+36^2=225+1296=1521$

$R_s=39^2=1521$

$L_s=R_s$

It's a right triangle.

6 0

3 years ago

Read 2 more answers

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz. An ornithologi

il63 [147K]

Answer:

The formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.7}{2} = 0.15$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.15 = 0.85$ , so Z = 1.037.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz.

This means that $\sigma = 0.04$ .

Sample of 10 birds:

This means that $n = 10$ .

The margin of error is of:

$M = z\frac{\sigma}{\sqrt{n}}$

$M = 1.037\frac{0.04}{\sqrt{10}}$

$M = 0.013$

The lower end of the interval is the sample mean of $\overline{x}$ subtracted by M.

The upper end of the interval is the sample mean of $\overline{x}$ added to M.

Then, the formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

8 0

3 years ago

How many possible circles of given radius can be drawn touching both axes and the line x = c?

DiKsa [7]

1 the answer is one

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4 years ago