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lisov135 [29]
3 years ago
6

Which element has the greatest ionization energy?

Chemistry
1 answer:
suter [353]3 years ago
5 0
Florine has the highest ionization energy due to the trend on the periodic table, going up and right the ionization energy will increase, francium being the lowest and helium the highest.
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You are given three beakers of unknown liquids. One beaker contains sugar water. Without tasting the liquids, how could you iden
Marrrta [24]

You would observe, trying to identify if there's a minimum difference in each beaker. Like, colour, or using an <em>bagueta </em>(idk how to say it in english), churning it or something like that.

8 0
3 years ago
What is temperature?
Alenkasestr [34]

Answer: Temperature is an objective measurement of how hot or cold an object is. It can be measured with a thermometer or a calorimeter. It is a means of determining the internal energy contained within a given system.

Explanation:

8 0
3 years ago
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What is the density of an object with 525 grams and a volume of 15cm3?
Hunter-Best [27]

Answer: 35 g/cm

Explanation:

Density equals mass over volume. 525 divided by 15 is 35

7 0
3 years ago
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Jeffrey is on his skateboard and starts skating down a ramp. Ten seconds later he is travelling at
AfilCa [17]

Answer: 2m/s^2

Explanation:

Velocity of skateboard = 20.0 m/s.

Time taken = Ten seconds (10 s)

Acceleration ​= ?

Recall that acceleration is the change in velocity of a body per unit time.

i.e Acceleration = (velocity / Time)

Acceleration = 20.0m/s ➗ 10 s

Acceleration = 2m/s^2

Thus, Jeffrey acceleration was 2m/s^2

7 0
4 years ago
You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of a
balandron [24]

Answer:

56.9 mmoles of acetate are required in this buffer

Explanation:

To solve this, we can think in the Henderson Hasselbach equation:

pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])

To make the buffer we know:

CH₃COOH  +  H₂O  ⇄   CH₃COO⁻  +  H₃O⁺     Ka

We know that Ka from acetic acid is: 1.8×10⁻⁵

pKa = - log Ka

pKa = 4.74

We replace data:

5.5 = 4.74 + log ([acetate] / 10 mmol)

5.5 - 4.74 = log ([acetate] / 10 mmol)

0.755 = log ([acetate] / 10 mmol)

10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)

5.69 = ([acetate] / 10 mmol)

5.69 . 10 = [acetate] → 56.9 mmoles

6 0
3 years ago
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