<u>Answer:</u> The volume of concentrated hydrochloric acid solution is 1.73 mL
<u>Explanation:</u>
To calculate the hydrogen ion concentration of the solution, we use the equation:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
pH = 1.60
Putting values in above equation, we get:
![1.60=-\log [H^+]](https://tex.z-dn.net/?f=1.60%3D-%5Clog%20%5BH%5E%2B%5D)
![[H^+]=10^{-1.60}=0.0251M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-1.60%7D%3D0.0251M)
To calculate the volume of the concentrated solution, we use the equation:

where,
are the molarity and volume of the concentrated HCl solution
are the molarity and volume of diluted HCl solution
We are given:

Putting values in above equation, we get:

Hence, the volume of concentrated hydrochloric acid solution is 1.73 mL
I hope this helps!!!!!!!!!!!
Answer : Option 3) Electrolysis.
Explanation : In the process of electrolysis, decomposition of the chemical is done by passing the electric current from the liquid or the solution containing ions in it. This is the process where compound is broken into ions namely, cations and anions.
Rest all options does not involves chemical decomposition of the compound.
Chromatography is a technique where rates of solute and solvent are compared in a medium where the solute components move at different rates and the separation is obtained.
Distillation simply purifies the liquid or solution by heating or cooling process.
Filtration just involves removal of impurities by using a more porous material device to get purified compound.
Its 470mg k dude or dudette
The empirical and molecular formula : C₂₁H₂₂N₂O₂
<h3>Further explanation</h3>
Given
The percent composition of an unknown substance is 75.42% Carbon, 6.63 % Hydrogen,
8.38 % Nitrogen, and 9.57 % Oxygen
Required
The empirical and molecular formula
Solution
C : 75.42 : 12 = 6.285
H : 6.63 : 1 = 6.63
N : 8.38 : 14 = 0.599
O : 9.57 : 16 = 0.598
Divide by 0.598
C : H : N : O = 10.5 : 11 : 1 : 1 = 21 : 22 : 2 : 2
The empirical formula : C₂₁H₂₂N₂O₂
(C₂₁H₂₂N₂O₂)n = 334
(334)n=334
n = 1