DO YOU WANT FREE POINTS AND BRAINLIEST JUST ANSWER THIS QUESTION
2 answers:
You might be interested in
Answer:
public static int powOfTwo(int input) {
return input*input;
}
You will have to call this method in main
for printing it, write
System.out.println(powOfTwo(your number));
in public static void main(str[]args) {
}
Answer:
Given values are:
We know that
1 MiB = = 1048576 bytes
1 MiB = x8= 8388608 bits
8MiB= 8388608x8 = 67108864 bits
So,
Total Number of bits = 67108864 bits
Now
Total link transmission rate = 44.2 Gbps
1 Gbps = 1000000000 bps
44.2 Gbps = 44.2 x 1000000000 =44200000000 bps
For FDM Network
Transmission rate for one time slot = bits per second
Transmission rate for one time slot = 4420000000 bit per second
Transmission rate for one time slot =
in milliseconds
Transmission rate for one time slot in =4420000 bits per millisecond
Now,
Total time taken to transmit 8 MiB of file =
Total time taken to transmit 8 MiB of file =
As setup time is also given So,
Total time = Setup time + Transmission Time
Total time = 85.1 + 15.18
Total time = 100.2 milliseconds
Hence it is the time required to send a 8MiB of file from Host A to Host B.
I hope it will hep you!