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Agata [3.3K]
4 years ago
9

Write the program to solve quadratic equations, but if the discriminant is negative, output

Computers and Technology
1 answer:
Firdavs [7]4 years ago
8 0

Answer:

PROGRAM  QuadraticEquation Solver

  IMPLICIT  NONE

REAL :: a, b, c ;

  REA :: d ;

  REAL  :: root1, root2 ;

//read in the coefficients a, b and c

  READ(*,*)    a, b, c  

  WRITE(*,*)   'a = ', a

  WRITE(*,*)   'b = ', b

  WRITE(*,*)    'c = ', c

  WRITE(*,*)

// computing the square root of discriminant d

  d = b*b - 4.0*a*c

  IF (d >= 0.0) THEN              //checking if it is solvable?

     d     = SQRT(d)

     root1 = (-b + d)/(2.0*a)     // first root

     root2 = (-b - d)/(2.0*a)     // second root

     WRITE(*,*)  'Roots are ', root1, ' and ', root2

  ELSE                            //complex roots

     WRITE(*,*)  'There is no real roots!'

     WRITE(*,*)  'Discriminant = ', d

  END IF

END PROGRAM  QuadraticEquationSolver

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Answer:

A. Source code

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terms = ["Bandwidth", "Hierarchy", "IPv6", "Software", "Firewall", "Cybersecurity", "Lists", "Program", "Logic",

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def swap(arr, in1, in2):

   w = arr[in1]

   arr[in1] = arr[in2]

   arr[in2] = w

print(terms)

swap(terms, 5, 1)

swap(terms, 2, 4)

swap(terms, 3, 5)

swap(terms, 5, 6)

swap(terms, 6, 8)

swap(terms, 8, 9)

print(terms)

This is how I interpreted the question. If I need to make any changes, I'll do my best. Hope this helps though.

4 0
3 years ago
14. In cell B14, create a formula without using a function that adds 1 to the value in cell B12 and then multiplies the result b
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Answer:

The formula for the given problem is given below:

= (1+B$12)×B13

Explanation:

Immediately you do one, then you can autofill the formula to the mentioned range B15:B17 and then to C14 to H17

When been done correctly, this is how the formula will look in those cells if you do it correctly.

Check the file attached below to see it.

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