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3 years ago

What is the domain of the function f given by f(x)=sqrt x^2-4/x-3?

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

7 0

In interval notation the domain would be: (-infinity,-2]U[2,3)U(3,+infinity)

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The value of varies directly with x. when y = 7.5 , x = 5. what is the value of y when x = 80?

AfilCa [17]

Answer:

x=120

$7.5 = 5 \\ x = 80 \\ \frac{5x}{5} = \frac{600}{5} \\ x = 120$

4 0

3 years ago

F(X) = 10x^3 find inverse

Korvikt [17]

1000 is you answer
Or
10x10x10
Or
10/3

3 0

3 years ago

Read 2 more answers

PLEASE HELP and show work

s2008m [1.1K]

Answer:

1. -2, -4

2. 7, ½

3. -2, -3

Step-by-step explanation:

1) -x² - 6x - 8 = 0

x² + 6x + 8 = 0

x² + 4x + 2x + 8 = 0

x(x + 4) + 2(x + 4) = 0

(x + 2)(x + 4) = 0

x = -2 , -4

2) 2x² - 15x + 7

2x² - 14x - x + 7 = 0

2x(x - 7) - (x - 7) = 0

(2x - 1)(x - 7) = 0

x = ½, 7

3) 3x² + 15x + 18 = 0

x² + 5x + 6 = 0

x² + 3x + 2x + 6 = 0

x(x + 3) + 2(x + 3) = 0

(x + 3)(x + 2) = 0

x = -2, -3

6 0

3 years ago

What are the solutions of the equation x6 + 6x3 + 5 = 0? Use factoring to solve.

Sergeu [11.5K]

Solution:

we have been asked to find the solution of the equation

$x^6 + 6x^3 + 5 = 0$

It can be solved using factoring as below:

$x^6 + 6x^3 + 5 = 0\\\\substitute, x^3=y\\\\y^2+6y+5=0\\\\y^2+5y+y+5=0\\\\y(y+5)+1(y+5)=0\\\\(y+5)(y+1)=0\\\\y=-1,-5\\\\\text{substitute back }y=x^3\\\\x^3=-1,-5\\\\x=-1,\sqrt[3]{-5} \\\\\text{These are the only real solutions}\\$

8 0

4 years ago

Read 2 more answers

29) PLEASE HELP WITH QUESTION.<br><br> MARKING BRAINLIEST + POINTS GIVEN.

Reika [66]

$x^{4} -32 x^{2} -144$ will factor into the following
$( x^{2} +4)( x^{2} -36)$
Set each factor equal to 0:
$x^{2} +4=0$ or $x^{2} -36=0$
$x^{2} =-4$ $x^{2} =36$
x = +/- 2i x = +/- 6

Answer: 2i, 6, -6

3 0

3 years ago