Answer:
The answer is 1,000
SInce the beginning number is 3 and there are ten possible numbers to put in the remaining three slots, there are exactly 1,000 possible combinations for a 3-digit code. The answer is 1,000. There are 3 rows of 10 digits. The number of combinations 10 to the thid power which is 1000 (10 * 10 * 10)
1.999… is exactly the number 2.
Let <em>x</em> = 1.999… . Then 1000<em>x</em> = 1999.999… . Subtract <em>x</em> from this to eliminate the fractional part, and you get
1000<em>x</em> - <em>x</em> = 1999.999… - 1.999…
1000<em>x</em> - <em>x</em> = 1999 - 1
999<em>x</em> = 1998
<em>x</em> = 1998/999 = 2/1 = 2
So <em>p</em> = 2 and <em>q</em> = 1.
Answer:
two which is B
Step-by-step explanation:
the lines only intersect twice
Let y be the balance in your account. Let x be the number of months.
y = 215 + (444-322)x = 215 + 122x
1000 = 215 + 122x
785 = 122x
x = 6.43 months
Answer:
Algebra =
X/4 = -5/20
Simplify :
X/4 = -1/4
Of course, Will same x/4 = -1/4
<h3>Answer : X = -1</h3>
