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igomit [66]
3 years ago
10

Given that YZ = 3.5, XZ = 16.4, and point Y lies on XZ , what is the length of XY?

Mathematics
2 answers:
photoshop1234 [79]3 years ago
6 0

Answer:

Step-by-step explanation:

Contact [7]3 years ago
5 0
It's the same as previous question
xz=xy+yz so 16.4=xz+3.5 so xz=16.4-3.5 =12.9
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Solve, using the substitution method.
inna [77]
Y - 2x = 8 . . . . (1)
16 + 4x = 2y . . (2)

From (1), y = 2x + 8 . . . (3)

Putting (3) into (2) gives
16 + 4x = 2(2x + 8) = 4x + 16
0 = 0

Therefore, there are infinite number of solutions.
8 0
4 years ago
Find the equation of the plane z = mx + ny + b which contains the points (0,0,6), (1,0,-3) and (0,2,5).
leonid [27]
The three points give you three equations, which you can solve by your favorite method.
.. 0m +0n +b = 6
.. 1m +0n +b = -3
.. 0m +2n +b = 5

(m, n, b) = (-9, -1/2, 6)
so the equation of the plane can be written as
.. z = -9x -1/2y +6

_____
In standard form, this would be
.. 18x +y +2z = 12

8 0
3 years ago
Please help me with this math problem
goldfiish [28.3K]
If you look at the graph you can tell the graph is increasing before x = -2. 

From x = -2 to x = 0, it's decreasing.

Then it's increasing again from x = 0 to x = 2, then decreasing after x = 2

So answer is the last one
It is increasing before x = -2 and from x = 0 to x = 2
3 0
4 years ago
On the first part of her trip Natalie rode her bike 16 miles and on the second part of the trip she rode her bike 42 miles. Her
-BARSIC- [3]

Answer:

14 mph   ( average speed during the second part of the trip )

Step-by-step explanation:

Let´s call  "x"  the average speed during the first part then

t = 5 hours

t  =  t₁  +  t₂        t₁   and  t₂   times during part 1 and 2 respectively

l = t*v           (  distance is speed by time )      t =  l/v

First part

t₁  = 16/x        and      t₂  = 42 / ( x + 6)

Then

t =   5   =  16/x   +   42 /(x + 6)

5 = [ 16 * ( x  +  6 ) +  42 * x ] / x* ( x + 6 )

5 *x * ( x + 6 )  =  16*x  + 96 +  42 x

5*x² + 30*x  - 58*x - 96  =  0

5*x²  -  28*x  -  96  =  0

We obtained a second degree equation, we will solve for x and dismiss any negative root since negative time has not sense

x₁,₂  =   [28 ± √ (28)² + 1920  ] / 10

x₁,₂  = ( 28  ± √2704 )/ 10

x₁  = 28  -  52 /10        we dismiss that root

x₂  = 80/10

x₂  =  8 mph       average speed during the first part, and the average speed in the second part was 6 more miles than in the firsst part. then the average spedd dring the scond part was 8 + 6 = 14 mph

6 0
4 years ago
T(r+4)=28 solve for t<br><br>pls help ​
Reptile [31]

Answer: 28/r+4

Step-by-step explanation: Divide each term by r + 4 and simplify

3 0
3 years ago
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