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Elan Coil [88]
3 years ago
10

John and Lisa have a two-month old baby. John feels that after the baby’s birth, love and sexual intimacy between him and Lisa h

as diminished. What is the action John should take?A.John should nag Lisa for not paying attention to him.
B.John should ignore Lisa and spend time out with friends.
C.John should just accept the situation and do nothing about it.
D.John should speak to Lisa and think of ways for them to spend time with each other.
Geography
1 answer:
tester [92]3 years ago
8 0
The answer is D.

Well, I would say that nagging someone is always a bad idea, especially if your wife just went through something like childbirth recently. Ignoring her isn't going to improve his relationship at all either if anything, it will hurt it. Just accepting and doing nothing will not make the relationship any better either. So the answer is D. Talk to and spend more time with her.
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Mexico’s war of independence from Spain in 1821 resulted in a political system that _____.
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Mexico’s war of independence from Spain in 1821 resulted in a political system that that was dominated by military dictators

<u>Explanation:</u>

After freedom, Mexican governmental was dominated by military dictators. The administration changed hands multiple times in the following 55 years (1821–76).  

The armed forces are influenced but did not rule directly which excludes personalist dictatorships, party dictatorships, and civilian governments. The Spanish endeavors to reconquer Mexico included scenes of war among Spain and the new country.

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Which type of rainfall is regularly found in the mountainous Northwestern US?
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Wasp-32b orbits with a period of only 2.7 days a star with a mass that is 1.1 times that of the sun. how many au from the star i
kaheart [24]
To solve this problem we will use Kepler's third law of planetary motion. Formula for that law is:
T^{2} = \frac{4  \pi ^{2} }{GM}  a^{3}
Where:
T = orbital period
G = universal gravitational constant
M = mass of star
a = distance from planet to star

By rearranging this formula we get:
\frac{T^{2}}{a^{3} } = \frac{4 \pi ^{2} }{GM}
For Earth we have:
\frac{365^{2}}{1^{3} } = \frac{4 \pi ^{2} }{GM}
For Wasp-32b we have:
\frac{2.7^{2}}{a^{3} } = \frac{4 \pi ^{2} }{G*1.1M} or
1.1* \frac{2.7^{2}}{a^{3} } = \frac{4 \pi ^{2} }{GM} 

We can see that right sides are same. Left sides must be same. We can use this to solve for distance.
\frac{365^{2}}{1^{3} } = 1.1* \frac{2.7^{2}}{a^{3}
\frac{365^{2}}{1.1* 2.7^{2}} = \frac{1}{a^{3} } \\ \\ 2.7^{2} =365^{2}*a^{3} \\ \\ a^{3} =\frac{2.7^{2} }{365^{2}} \\ \\ a= \sqrt[3]{\frac{2.7^{2} }{365^{2}} } \\ \\ \\ a=0.038AU

Wasp-32b is at distance of 0.038AU.
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