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3 years ago

X divided by A equals Y plus ZX divided by B

Mathematics

1 answer:

Lunna [17]3 years ago

3 0

I don’t think there is a solution

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What is the rate of change from x = n to x = 2n?

puteri [66]

Answer:

$\dfrac{-8}{\pi}$

Step-by-step explanation:

The rate of change of the function f(x) from point $x_1$ to point $x_2$ can be calculated using formula

$\dfrac{f(x_2)-f(x_1)}{x_2-x_1}$

Given

$x_1=\pi\\ \\x_2=2\pi$

From the graph of the function

$f(x_1)=f(\pi)=4\\ \\f(x_2)=f(2\pi)=-4$

So, the rate of change is

$\dfrac{f(x_2)-f(x_1)}{x_2-x_1}=\dfrac{-4-4}{2\pi -\pi}=\dfrac{-8}{\pi}$

5 0

3 years ago

BRAINLIESTT ASAP! PLEASE HELP ME :)

antiseptic1488 [7]

Step-by-step explanation:

$\displaystyle y = Acos(Bx - C) + D$

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

$\displaystyle Phase\:[Horisontal]\:Shift → \frac{-\frac{2}{3}π}{2} = -\frac{π}{3} \\ Period → \frac{2}{2}π = π$

Therefore we have our answer.

Extended Information on the trigonometric function

$\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|$

NOTE: Sometimes, your vertical shift might tell you to shift your graph below or above the midline where the amplitude is.

I am joyous to assist you anytime.

3 0

3 years ago

Read 2 more answers

the hardcover version of a book weighs 7 ounces while its paperback version weighs 5 ounces. Forty-five copies of the book weigh

Nuetrik [128]

Keywords:

System of equations, variables, hardcover version, paperback version, books

For this case we must construct a system of two equations with two variables. Let "h" be the number of hardcover version books, and let "p" be the number of paperback version books. If the hardcover version of a book weighs 7 ounces and the paperback version weighs 5 ounces, to reach a total of 249 ounces we have:

$7h + 5p = 249$ (1)

On the other hand, if there are Forty-five copies of the book then:

$h + p = 45$ (2)

If from (2) we clear the number of books paperback version we have:

$p = 45-h$

As each paperback version book weighs 5 ounces, to obtain the total weight of the paperback version books, represented by "x" in the table shown, we multiply $5 * p = 5 (45-h)$