All categories

3 years ago

Please help me because I don't understand how to do it.:)

Mathematics

1 answer:

lana66690 [7]3 years ago

8 0

Answer:

C Yes, 75+ 2.5*60 = 225

Step-by-step explanation:

The charges for the electrician

1st hour = 75

Additional hours 60

We have 3 1/2 hours of labor

The first hour is 75 dollars

3 1/2 - 1 = 2 1/2

There will be 2 1/2 hours at the 60 dollar rate

75 + 60 * 2.5 =

75 + 150

225

You might be interested in

Naya and Scott have a cleaning business, Naya can clean the office suite in 20 minutes less time than it takes Scott to do the s

Rina8888 [55]

B
Explanation: idk i just want pts

6 0

3 years ago

Part A

Ber [7]

Answer:learn your self

Step-by-step explanation:

Lol

7 0

2 years ago

What is the y intercept of the line whose equation is y = 1/2x - 3

den301095 [7]

The y intercept is when x=0 so y=1/2(0) -3 so y=0-3 so y=-3

7 0

3 years ago

Read 2 more answers

Evaluate log4 7 using the change of base formula. Round your answer to the nearest thousandth. Show all work.

uranmaximum [27]

$\log _47\text{ = }$

3 0

1 year ago

Approximate the integral integral integral integral f(x, y) dA by dividing the rectangle R with vertices (0, 0), (4, 0), (4, 2),

amm1812

Answer:

Step-by-step explanation:

Approximate the integral $\int\int\limits_R {f(x,y)} \, dA$ by dividing the region $R$ with vertices (0,0),(4,0),(4,2) and (0,2) into eight equal squares.

Find the sum $\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i$

Since all are equal squares, so $\delta A_i=1$ for every $i$

$\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=f(x_1,y_1)\delta A_1+f(x_2,y_2)\delta A_2+f(x_3,y_3)\delta A_3+f(x_4,y_4)\delta A_4+f(x_5,y_5)\delta A_5+f(x_6,y_6)\delta A_6+f(x_7,y_7)\delta A_7+f(x_8,y_8)\delta A_8\\\\=f(0.5,0.5)(1)+f(1.5,0.5)(1)+f(2.5,0.5)(1)+f(3.5,0.5)(1)+f(0.5,1.5)(1)+f(1.5,1.5)(1)+f(2.5,1.5)(1)+f(3.5,1.5)(1)\\\\=0.5+0.5+1.5+0.5+2.5+0.5+3.5+0.5+0.5+1.5+1.5+1.5+2.5+1.5+3.5+1.5\\\\=24$

Thus, $\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=24$

Evaluating the iterate integral $\int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=\int\limits^4_0 {[xy+\frac{y^2}{2} ]}\limits^2_0 \, dx =\int\limits^4_0 {[2x+2]}dx\\\\=[x^2+2x]\limits^4_0=24.$

Thus, $\int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=24$

7 0

2 years ago