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PSYCHO15rus [73]
3 years ago
10

Find the smallest integer a > 2 such that 2/a, 3/a+1, 4/a+2, 5/a+3, 6/a+4

Mathematics
1 answer:
olga55 [171]3 years ago
8 0

Answer:

62

Step-by-step explanation:

we have given a> 2

then \frac{2}{a}\ ,\frac{3}{a+1}\ ,\frac{4}{a+2}\ , \frac{5}{a+3}\ ,\frac{6}{a+4}

since it is given that a> 2

so a\equiv 2\ mod\ 4  a\equiv 2\ mod\ 5  a\equiv 2\ mod\ 6

a\equiv2 \left ( mod\ 2,3,4,5,6 \right )

a\equiv2 \left ( mod\ lcm\left ( 2,3,4,5,6 \right )\right )

a\equiv2 \left ( mod\ 60 \right )

then a=60n+2 where n is a positive integer

so smallest value of a is a=60×1+2=62

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Answer:

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Step-by-step explanation:

Given the expression x² + 16x + 14 = 0

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Hence the required solutions are -8+5√2 and -8-5√2

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  • \frac{1}{cos^{2}y } = 1+tan^{2}y => \frac{1}{(3/5)^{2} } = 1 + tan^{2} y => tan^{2}y=\frac{16}{9}

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