We know that if we had
8/6=2/2 times 4/3=1 times 4/3=4/3
find common factors in top and obttom
factor
48a^4-16a^2-32=(16)(a-1)(a+1)(3a^2+2)
8a^2-8=8(a-1)(a+1)
so we have
(2)(3a^2+2)=6a^2+4
answer is 6a^2+4
Answer:
28.26
Step-by-step explanation:
I hope this helps!
5) The relation between intensity and current appears linear for intensity of 300 or more (current = intensity/10). For intensity of 150, current is less than that linear relation would predict. This seems to support the notion that current will go to zero for zero intensity. Current might even be negative for zero intensity since the line through the points (300, 30) and (150, 10) will have a negative intercept (-10) when current is zero.
Usually, we expect no output from a power-translating device when there is no input, so we expect current = 0 when intensity = 0.
6) We have no reason to believe the linear relation will not continue to hold for values of intensity near those already shown. We expect the current to be 100 for in intensity of 1000.
8) Apparently, times were only measured for 1, 3, 6, 8, and 12 laps. The author of the graph did not want to extrapolate beyond the data collected--a reasonable choice.
Answer:
the geometric series is a(n) = -12(3)^(n-1)
Step-by-step explanation:
"Triple" denotes multiplication by 3. Thus, the common factor here is 3.
The general formula for a geometric series is a(n) = a(1)(r)^(n-1), where a(1) is the first term, r is the common ratio.
Here, we have a(n)= (-12)(3)^(n-1) = -972.
We need to solve this for n, which represents the last term.
The first step towards solving for n is to divide both sides by -12:
3^(n-1) = 81
To solve for n-1, rewrite 81 as 3^4. Then we have:
3^(n-1) = 3^4, implying that (n-1) = 4 and that n = 5.
Then we know that it is the 5th term that equals -972.
In summary, the geometric series is a(n) = -12(3)^(n-1).
