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Rudik [331]
3 years ago
11

Multiplying decimals with models

Mathematics
2 answers:
Sidana [21]3 years ago
6 0
1 is 0.0012. 2 is 3.25 and 3 is 3.25
pav-90 [236]3 years ago
5 0
Number one is 0.0012
Number two is 0.0028
Number three is 3.25
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What is 7√11√ in simplest radical form? Enter your answer in the box.
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23.21 is the answer i believe

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Which fraction is NOT equivalent to 0.75? A. 15/20 B. 9/12 C. 6/9 D. 3/4
astraxan [27]
The answer is c, 6/9, because 0.75 equals 3/4 in fraction form, and 6/9 reduces to 2/3.
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When y is 4, p is 0. 5, and m is 2, x is 2. If x varies directly with the product of p and m and inversely with y, which equatio
dmitriy555 [2]

Answer:

  \dfrac{xy}{pm}=8

Step-by-step explanation:

If x varies directly as the product of p and m, and inversely with y, the relation can be written ...

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This can be solved for k:

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For the given values, the value of k is ...

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Then the relation between the variables can be written ...

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5 0
2 years ago
Suppose you deposit ​$600 in a bank account with a simple interest rate of 2.5​%. You want to keep your deposit in the bank long
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Answer:

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Step-by-step explanation:

7 0
3 years ago
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Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us.
mestny [16]

For a binomial experiment in which success is defined to be a particular quality or attribute that interests us, with n=36 and p as 0.23,  we can approximate p hat by a normal distribution.

Since n=36 , p=0.23 , thus q= 1-p = 1-0.23=0.77

therefore,

n*p= 36*0.23 =8.28>5

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and therefore, p hat can be approximated by a normal random variable, because n*p>5 and n*q>5.

The question is incomplete, a possible complete question is:

Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us.

Suppose n = 36 and p = 0.23. Can we approximate p hat by a normal distribution? Why? (Use 2 decimal places.)

n*p = ?

n*q = ?

Learn to know more about binomial experiments at

brainly.com/question/1580153

#SPJ4

3 0
2 years ago
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