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Viktor [21]
3 years ago
8

Which of the equations listed below are linear equations?

Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

I think the answer is D.

If not juts look up a linear equation calculator and it will tell you.

Hope this helps :)

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a half of whats johns age was 4 years ago is equal to one third of what will be in 5 years time. how old is john now?
Leona [35]

Let x = John's age now

half of what johns age was 4 years ago: (1/2)(x-4)

is equal to one third of what it will be in 5 years time: (1/3)(x+5)

 

(1/2)(x-4) = (1/3)(x+5)

 

3(x-4) = 2(x+5)

 

3x - 12 = 2x + 10

8 0
3 years ago
Use the position equation given below, where s represents the height of the object (in feet), v0 represents the initial velocity
iris [78.8K]

Answer:

(a) 7.5 seconds

(b) The horizontal distance the package  travel during its descent is 1737.8 ft

Step-by-step explanation:

(a) The given function for the height of the object is s = -16·t² + v₀·t + s₀

The initial height of the object s₀ = 900 feet

The initial vertical velocity of the object v₀_y = 0 m/s

The time it takes the package to strike the ground is found as follows;

0 = -16·t² + 0×t + 900

900 = 16·t²

t² = 900/16 = 62.25

t = √62.25 = 7.5 seconds

(b) Given that the horizontal velocity of the package is given as 158 miles/hour, we have

158 miles/hour = 231.7126 ft/s

The horizontal distance the package  covers in the 7.5 second of vertical flight = 231.7126 ft/s × 7.5 s = 1737.8445 feet = 1737.8 ft to one decimal place

The horizontal distance the package  travel during its descent = 1737.8 ft.

4 0
3 years ago
Plot the numbers −1 3/4 and 5/2 on the number line below.
katovenus [111]

Answer:

Hey so I graphed it for you in the picture, It should be between 2 and 3

8 0
3 years ago
Is 660 10 times as much as 600?
Serggg [28]
No it's not. hope I helped
6 0
3 years ago
Read 2 more answers
The center of a circle is the point (3, 2). if the point (6, −2) lies on this circle, find the standard equation for the circle.
garri49 [273]
Given 
centre of circle O(3,2)=O(x0,y0)
point on circle P(6,-2)

Standard equation of circle:
(x-x0)^2+(y-y0)^2=r^2

r=radius of circle
= (distance OP)
= sqrt((6-3)^2+(-2-2)^2)
=sqrt(3^2+(-4)^2)
=sqrt(25)

=> 
r^2=(sqrt(25))^2=25

Equation of circle
(x-x0)^2+(y-y0)^2=r^2
(x-3)^2+(y-2)^2=25   ............... standard equation of circle
5 0
4 years ago
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