The initial dimenssions of the park lot are:
length: 140 ft
width: 90 ft
initial area: 140 * 90 = 12,600 ft^2
Area increased 29% = 12,600 * 1.29 = 16,254 ft^2
width of the strips: x
New length: 140 + x
New width: 90 + x
New area: (140+x)(90+x) = 16,254
Solution of the equation:
12600 + 230x + x^2 = 16254
=> x^2 + 230x - 3654 = 0
Use the quadratic formula.
x = {-230 +/- √[ 230^2 - 4*1*(-3654) ]} / 2 =
x = 14.92
The other solution is negative so it is discarded.
Answer: 15 ft
Answer:
the markup is 1016%
Step-by-step explanation:
-7 ÷ 2 1/2
Okay, so first, put the -7 over one and make 2 1/2 an improper fraction. so now:
-7/1 ÷ 5/2
Then, take the reciprocal of 5/2 and multiply it by -7/1
-7/1 × 5/2
Which would be -35/2
The mean increases. When Deleware (2,000: 2) is included the mean must be divided by 9 instead of 8.
Answer:
The variable that may change in response to the increase of the drug is the GAD symptoms by a 37,5%.
Step-by-step explanation:
According to the results of the first experiment with a mass of 200 mg of Drug R, they obtain a reduced of the GAD symptoms by a 25 percent evidenced by the Hamilton Anxiety Scale.
If they decided to increase the mass of Drug R to 300 mg the results expected are a increase of the porcentange of the reduced symptoms of generalized anxiety disorder, according to the tendence of the first hypothesis and the Hamilton Anxiety Scale.
We can express this increase by using the three simple rule. Where if 200 mg of Drug R reduced the 25% of the GAD symptoms, if we increase to 300 mg of Drug R how much porcentage this amount will be reduced.
Doing the maths 300mg × 25%=7500mg%,
⇒ 7500mg% ÷ 200mg = 37,5%.
<u>In conclusion</u> if they increased the mas of Drug R to 300 mg they will be reduced the generalized anxiety disorder (GAD) to a 37,5%.
