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Levart [38]
3 years ago
11

What is the domain of the function on the graph?

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
6 0
I think it’s x>=-3
That means greater than or equal to btw :)
Lina20 [59]3 years ago
3 0

Answer: The answer is [-3,\infty).

Step-by-step explanation:  We are given to find the domain of the function that is graphed in the figure.

We can see from the graph that the values of x will give the domain and the corresponding values of y will give the range of the function.

Since the values of x does not go beyond -3 on the negative X-axis and it goes to infinity on the positive X- axis, so the domain will be greater than or equal to -3.

Thus, the required domain is [-3,\infty].

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4 0
3 years ago
Identify the range of the function shown in the graph.<br>​
lys-0071 [83]

Answer:

C. 0 ≤ y ≤ 8

Step-by-step explanation:

In any graph, the range represents the 'y' values covered by the graph.  The 'y' axis is the vertical (up and down) line on the graph.  Given the graph, it stops at the point (0, 8) on the top and at (-6,0) and (6,0) on the bottom.  This would be an overall range of 0 ≤ y ≤ 8.

7 0
4 years ago
Right answer gets brainlyest
earnstyle [38]

Answer:

-\frac{7}{8}a-\frac{1}{6} (the first box is 7/8 and the second box is 1/6)

Step-by-step explanation:

Step 1: Combine like terms.

  • (-\frac{5}{8}a-\frac{1}{4}a)+(\frac{2}{3}  -\frac{5}{6})
  • (-\frac{5}{8}a -\frac{2}{8}a)+(\frac{4}{6}-\frac{5}{6})
  • -\frac{7}{8}a-\frac{1}{6}

Therefore, the answer is -\frac{7}{8}a-\frac{1}{6}. (Again, the first box is 7/8 and the second box is 1/6).

5 0
3 years ago
father is three times as old as his son. if the difference of their ages is 24 years, find their present age​
miskamm [114]

Step-by-step explanation:

Let x be the son's age. The father's age is 3x and 3x - x = 24.

Therefore 2x = 24 and x = 12.

The son's age is 12 and the father's age is 36 at present.

8 0
3 years ago
Answer these three for me pls guys
Nataliya [291]
11) X= 7, X= -7
(X+7)(X-7)=X^2+7X-7X-49=X^2-49

8 0
4 years ago
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